6(A+B)^2X^2 + 5(a+b)cx - 6c^2 = 0

Solve BY Sridharacharya formula..

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6(A+B)^2X^2 + 5(a+b)cx - 6c^2 = 0
Solve BY Sridharacharya formula

Ankush Jain · Accepted Answer

We have, 6(a + b)2x2 + 5(a+b)cx - 6c2 = 0 Sridharacharya formula is the another name of quadratic formula

$\Rightarrow x = \frac{- 5 (a + b) c \pm \sqrt{{[5 (a + b) c]}^{2} - 4 \times 6 (a + b)^{2} \times (- 6 c^{2})}}{2 \times 6 (a + b)^{2}} \Rightarrow x = \frac{- 5 (a + b) c \pm \sqrt{{[(a + b) c]}^{2} (25 + 144)}}{2 \times 6 (a + b)^{2}} \Rightarrow x = \frac{- 5 (a + b) c \pm \sqrt{{[(a + b) c]}^{2} (169)}}{2 \times 6 (a + b)^{2}} \Rightarrow x = \frac{- 5 (a + b) c \pm \sqrt{{[(a + b) c]}^{2} (13 \times 13)}}{2 \times 6 (a + b)^{2}} \Rightarrow x = \frac{- 5 (a + b) c \pm 13 (a + b) c}{2 \times 6 (a + b)^{2}} \Rightarrow x = \frac{- 5 (a + b) c + 13 (a + b) c}{2 \times 6 (a + b)^{2}} o r x = \frac{- 5 (a + b) c - 13 (a + b) c}{2 \times 6 (a + b)^{2}} \Rightarrow x = \frac{8 (a + b) c}{12 (a + b)^{2}} o r x = \frac{- 18 (a + b) c}{12 (a + b)^{2}} \Rightarrow x = \frac{2 c}{3 (a + b)} o r x = \frac{- 3 c}{2 (a + b)}$

6(A+B)^2X^2 + 5(a+b)cx - 6c^2 = 0 Solve BY Sridharacharya formula..

6(A+B)^2X^2 + 5(a+b)cx - 6c^2 = 0

Solve BY Sridharacharya formula..