3 mol of an ideal gas at 1 5 atm and 25 degree celsius expands isothermally in a reversible manner - Chemistry - Thermodynamics

Question

3 mol of an ideal gas at 1 5 atm and 25 degree celsius expands
isothermally in a reversible manner to twice the original volume
against an external pressure of 1 atm calculate the work done

Chandra Prakash · Accepted Answer

n = 2 mole P = 1 5
atm T = 25Â°C = 298K

P = 1 atm
V1 = V V2 = 2V

Formula:

W = -2 303 nRT
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Putting the value
of parameter in above formula, and calculate the work
done

W = -2 303 x 2 x 0
082 x 298 x log2

= -2 303 x 2 x 0
082 x 298 x 0 3010

= -33 878 joule
energy will be absorbed by the system

3 mol of an ideal gas at 1.5 atm and 25 degree celsius expands isothermally in a reversible manner to twice the original volume against an external pressure of 1 atm. calculate the work done....