13.Q. The function f(x) = 2tan3x-3tan2x+12tanx +3,  ( 0 ,   π 2 )  is,

(A) increasing                   (B) decreasing
(C) increasing in (0,  π / 4 ) a n d   d e c r e a sin g   i n ( π / 4 ,   π / 2 )
(D) none of these

fx=2tan3x+3tan2x+12 tan x+3f'x=6 tan2x sec2x+6 tan x sec2x+12 sec2x=6sec2xtan2x+tan x+2Note: 6sec2x>0 and tan x>0 in x0, π2, therefore f'x>0 Hence fx is increasing

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