1)if at a moment t=0,the separation between two cars is 100m,the separation between the at t=2s

2)Twocars start from the same point on a straight road due north.While carA starts with initial velocity 10m/s and a=1m/s^2,carB starts from rest and has an acceleration of 2m/s^2.answer the question. 1)the moment of time at which the separation of the cars is same as that of t=5s is?

1) Data seems to be incomplete to solve the question. Kindly recheck it and then post again.
2)
Given that,
uA=10 m/s, aA=1 m/s2uB=0,aB=2m/s2Distance travelled by car in 5 seconds,sA=uAt+12aAt2=10×5+12×1×52=62.5 mand sB=uBt+12aBt2=0+12×2×52=25 mSeparation between the cars=sA-sB=62.5-25=37.5 mSuppose after time t', the separation is again 37.5 mSo, sA-sB=(uAt'+12aAt'2)-(uBt'+12aBt'2)37.5=(10t'+121×t'2)-(0+12×2×t'2)On solving,we get t'=15
Thus,
After 15 seconds, the separation of the cars is same as that of t=5s

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