Mathematics Solutions Solutions for Class 8 Maths Chapter 11 Division Of Polynomials are provided here with simple step-by-step explanations. These solutions for Division Of Polynomials are extremely popular among class 8 students for Maths Division Of Polynomials Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Mathematics Solutions Book of class 8 Maths Chapter 11 are provided here for you for free. You will also love the ad-free experience on Meritnation’s Mathematics Solutions Solutions. All Mathematics Solutions Solutions for class 8 Maths are prepared by experts and are 100% accurate.
Page No 64:
Question 1:
Divide. Write the quotient and the remainder.
(1) 21m2 ÷ 7m
(2) 40a3 ÷ (−10a)
(3) (−48p4) ÷ (−9p2)
(4) 40m5 ÷ 30m3
(5) (5x3 − 3x2) ÷ x2
(6) (8p3 − 4p2) ÷ 2p2
(7) (2y3 + 4y2 + 3) ÷ 2y2
(8) (21x4 − 14x2 + 7x) ÷ 7x3
(9) (6x5 − 4x4 + 8x3 + 2x2) ÷ 2x2
(10) (25m4 − 15m3 + 10m + 8) ÷ 5m3
Answer:
(1) 21m2 ÷ 7m
So, quotient = 3m and remainder = 0
(2) 40a3 ÷ (−10a)
So, quotient = and remainder = 0
(3) (−48p4) ÷ (−9p2)
So, quotient = and remainder = 0.
(4) 40m5 ÷ 30m3
So, quotient = and remainder = 0.
(5) (5x3 − 3x2) ÷ x2
So, quotient = and remainder = 0
(6) (8p3 − 4p2) ÷ 2p2
So, quotient = and remainder = 0
(7) (2y3 + 4y2 + 3) ÷ 2y2
So, quotient = and remainder = 3
(8) (21x4 − 14x2 + 7x) ÷ 7x3
So, quotient = 3x and remainder =
(9) (6x5 − 4x4 + 8x3 + 2x2) ÷ 2x2
So, quotient = and remainder = 0
(10) (25m4 − 15m3 + 10m + 8) ÷ 5m3
So, quotient = and remainder =
Page No 66:
Question 1:
Divide and write the quotient and the remainder.
(1) (y2 + 10y + 24) ÷ (y + 4)
(2) (p2 + 7p − 5) ÷ (p + 3)
(3) (3x + 2x2 + 4x3) ÷ (x − 4)
(4) (2m3 + m2 + m + 9) ÷ (2m − 1)
(5) (3x − 3x2 − 12 + x4 + x3) ÷ (2 + x2)
(6) (a4 − a3 + a2 − a + 1) ÷ (a3 − 2)
(7) (4x4 − 5x3 − 7x + 1) ÷ (4x − 1)
Answer:
(1) (y2 + 10y + 24) ÷ (y + 4)
So, quotient = y + 6 and remainder = 0
(2) (p2 + 7p − 5) ÷ (p + 3)
So, quotient = p + 6 and remainder = 17.
(3) (3x + 2x2 + 4x3) ÷ (x − 4)
So, quotient = and remainder = 300.
(4) (2m3 + m2 + m + 9) ÷ (2m − 1)
So, quotient = and remainder = 10.
(5) (3x − 3x2 − 12 + x4 + x3) ÷ (2 + x2)
So, quotient = and remainder = x 2.
(6) (a4 − a3 + a2 − a + 1) ÷ (a3 − 2)
So, quotient = and remainder = .
(7) (4x4 − 5x3 − 7x + 1) ÷ (4x − 1)
So, quotient = and remainder = .
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