Mathematics Solutions Solutions for Class 7 Maths Chapter 2 Multiplication And Division Of Integers are provided here with simple step-by-step explanations. These solutions for Multiplication And Division Of Integers are extremely popular among Class 7 students for Maths Multiplication And Division Of Integers Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Mathematics Solutions Book of Class 7 Maths Chapter 2 are provided here for you for free. You will also love the ad-free experience on Meritnation’s Mathematics Solutions Solutions. All Mathematics Solutions Solutions for class Class 7 Maths are prepared by experts and are 100% accurate.

#### Question 1:

Multiply.
(i)      $\left(-5\right)×\left(-7\right)$
(ii)     $\left(-9\right)×\left(6\right)$
(iii)    $\left(9\right)×\left(-4\right)$
(iv)    $\left(8\right)×\left(-7\right)$
(v)     $\left(-124\right)×\left(-1\right)$
(vi)    $\left(-12\right)×\left(-7\right)$
(vii)   $\left(-63\right)×\left(-7\right)$
(viii)  $\left(-7\right)×\left(15\right)$

(i)      $\left(-5\right)×\left(-7\right)=35$
(ii)     $\left(-9\right)×\left(6\right)=-54$
(iii)    $\left(9\right)×\left(-4\right)=-36$
(iv)    $\left(8\right)×\left(-7\right)=-56$
(v)     $\left(-124\right)×\left(-1\right)=124$
(vi)    $\left(-12\right)×\left(-7\right)=84$
(vii)   $\left(-63\right)×\left(-7\right)=441$
(viii)  $\left(-7\right)×\left(15\right)=-105$

#### Question 1:

Solve :
(i)      $\left(-96\right)÷16$
(ii)     $98÷\left(-28\right)$
(iii)    $\left(-51\right)÷68$
(iv)    $38÷\left(-57\right)$
(v)     $\left(-85\right)÷20$
(vi)    $\left(-150\right)÷\left(-25\right)$
(vii)   $100÷60$
(viii)  $9÷\left(-54\right)$
(ix)    $78÷65$
(x)     $\left(-5\right)÷\left(-315\right)$

(i)      $\left(-96\right)÷16=-6$
(ii)     $98÷\left(-28\right)=\frac{-7}{2}$
(iii)    $\left(-51\right)÷68=\frac{-3}{4}$
(iv)    $38÷\left(-57\right)=\frac{-2}{3}$
(v)     $\left(-85\right)÷20=\frac{-17}{4}$
(vi)    $\left(-150\right)÷\left(-25\right)=6$
(vii)   $100÷60=\frac{5}{3}$
(viii)  $9÷\left(-54\right)=\frac{-1}{6}$
(ix)    $78÷65=\frac{6}{5}$
(x)     $\left(-5\right)÷\left(-315\right)=\frac{1}{63}$

#### Question 2:

Write three divisions of integers such that the fractional form of each will be $\frac{24}{5}$ .

The three divisions of integers are .

#### Question 3:

Write three divisions of integers such that the fractional form of each will be $\frac{-5}{7}$ .

$\frac{-5}{7}×\frac{3}{3}=\frac{-15}{21}\phantom{\rule{0ex}{0ex}}\frac{-5}{7}×\frac{4}{4}=\frac{-20}{28}\phantom{\rule{0ex}{0ex}}\frac{-5}{7}×\frac{5}{5}=\frac{-25}{35}$
Hence, the three divisions of integers are  .

#### Question 4:

The fish in the pond below, carry some numbers. Choose any 4 pairs and carry out four multiplications with those numbers. Now, choose four other pairs and carry out divisions with these numbers.
For example,
1. (–13) × (–15) = 195
2. $\left(-24\right)÷9=\frac{-24}{9}-\frac{-8}{3}$

The four such multiplications are
(−13) × 9 = 117
(−15) × 12 = −180
(−8) × (−18) = 144
13 × 41 = 533
The four such division are
(−18) ÷ 9 = −2
(−24) ÷ 12 = −2
(−13) ÷ 13 = −1
(−27) ÷ 9 = −3

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