RS Aggarwal 2020 2021 Solutions for Class 7 Maths Chapter 9 Unitary Method are provided here with simple step-by-step explanations. These solutions for Unitary Method are extremely popular among class 7 students for Maths Unitary Method Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the RS Aggarwal 2020 2021 Book of class 7 Maths Chapter 9 are provided here for you for free. You will also love the ad-free experience on Meritnation’s RS Aggarwal 2020 2021 Solutions. All RS Aggarwal 2020 2021 Solutions for class 7 Maths are prepared by experts and are 100% accurate.

Page No 133:

Question 1:

Answer:

Cost of 15 oranges = Rs 110

Cost of 1 orange = Rs 11015
∴ Cost of 39 oranges = Rs 11015×39 = Rs 286

Page No 133:

Question 2:

Cost of 15 oranges = Rs 110

Cost of 1 orange = Rs 11015
∴ Cost of 39 oranges = Rs 11015×39 = Rs 286

Answer:

Amount of sugar bought for Rs 260 = 8 kg
Amount of sugar bought for Re 1 = 8260 kg
Now, amount of sugar bought for Rs 877.50 = 8260×877.50 kg = 27 kg

∴ 27 kg of sugar can be bought for Rs 877.50.

Page No 133:

Question 3:

Amount of sugar bought for Rs 260 = 8 kg
Amount of sugar bought for Re 1 = 8260 kg
Now, amount of sugar bought for Rs 877.50 = 8260×877.50 kg = 27 kg

∴ 27 kg of sugar can be bought for Rs 877.50.

Answer:

Length of the silk purchased for Rs 6290  = 37 m
Length of the silk purchased for  Re 1= 376290 m
Now, length of the silk purchased for Rs 4,420 = 376290×4420 m = 26 m
∴ 26 m of silk can be purchased for Rs 4,420.

Page No 133:

Question 4:

Length of the silk purchased for Rs 6290  = 37 m
Length of the silk purchased for  Re 1= 376290 m
Now, length of the silk purchased for Rs 4,420 = 376290×4420 m = 26 m
∴ 26 m of silk can be purchased for Rs 4,420.

Answer:

Number of days for which a worker is paid Rs 1,110 = 6
Number of days for which a worker is paid Re 1 = 61110 days
Now, number of days for which a worker is paid Rs 4625=61110×4625 days = 25 days
∴ The worker worked 25 days in a month.

Page No 133:

Question 5:

Number of days for which a worker is paid Rs 1,110 = 6
Number of days for which a worker is paid Re 1 = 61110 days
Now, number of days for which a worker is paid Rs 4625=61110×4625 days = 25 days
∴ The worker worked 25 days in a month.

Answer:

Distance covered by the car with 42 L of petrol = 357 km
Distance covered by the car with 1 L of petrol = 35742 km             [less petrol, less distance]
Now, distance covered by the car with 12 L of petrol = 35742×12 = 102 km   [more petrol, more distance]

Page No 133:

Question 6:

Distance covered by the car with 42 L of petrol = 357 km
Distance covered by the car with 1 L of petrol = 35742 km             [less petrol, less distance]
Now, distance covered by the car with 12 L of petrol = 35742×12 = 102 km   [more petrol, more distance]

Answer:

Cost of travelling 900 km by train = Rs 2520

Cost of travelling 1 km by train = Rs 2520900
Now, cost of travelling 360 km by train =Rs 2520900×360 = Rs 1008
∴ The train fare for a journey of distance 360 km is Rs 1,008.

Page No 133:

Question 7:

Cost of travelling 900 km by train = Rs 2520

Cost of travelling 1 km by train = Rs 2520900
Now, cost of travelling 360 km by train =Rs 2520900×360 = Rs 1008
∴ The train fare for a journey of distance 360 km is Rs 1,008.

Answer:

Time taken to cover a distance of 51 km = 45 min

Time taken to cover a distance of 1 km = 4551 min

Time taken to cover distance of 221 km = 4551×221 min = 195 min = 3 h 15 min

∴ The train will take 3 h 15 min to cover a distance of 221 km.

Page No 133:

Question 8:

Time taken to cover a distance of 51 km = 45 min

Time taken to cover a distance of 1 km = 4551 min

Time taken to cover distance of 221 km = 4551×221 min = 195 min = 3 h 15 min

∴ The train will take 3 h 15 min to cover a distance of 221 km.

Answer:

Length of the iron rod that weighs 85.5 kg = 22.5 m
Length of the iron rod that weighs 1 kg = 22.585.5 m               [less weight, less length]
∴ Length of the iron rod that weighs 22.8 kg = 22.585.5×22.8 m = 6 m       [more weight, more length]

Page No 133:

Question 9:

Length of the iron rod that weighs 85.5 kg = 22.5 m
Length of the iron rod that weighs 1 kg = 22.585.5 m               [less weight, less length]
∴ Length of the iron rod that weighs 22.8 kg = 22.585.5×22.8 m = 6 m       [more weight, more length]

Answer:

Number of paper sheets that weighs 162 g = 6
Number of paper sheets that weighs 1 g = 6162                  [less weight, less sheets]
∴ Number of paper sheets that weighs 13.5 kg = 6162×13.5×1000 = 500    [more weight, more sheets]

Page No 133:

Question 10:

Number of paper sheets that weighs 162 g = 6
Number of paper sheets that weighs 1 g = 6162                  [less weight, less sheets]
∴ Number of paper sheets that weighs 13.5 kg = 6162×13.5×1000 = 500    [more weight, more sheets]

Answer:

Number of cartons needed to pack 1152 soap bars = 8
Number of cartons needed to pack 1 soap bar = 81152              [less number of soaps, less number of cartons needed] 
Now, number of cartons needed to pack 3888 soap bars = 81152×3888 = 27        [more soaps, more carton needed]

∴ 27 cartons are needed to pack 3888 soap bars.

Page No 133:

Question 11:

Number of cartons needed to pack 1152 soap bars = 8
Number of cartons needed to pack 1 soap bar = 81152              [less number of soaps, less number of cartons needed] 
Now, number of cartons needed to pack 3888 soap bars = 81152×3888 = 27        [more soaps, more carton needed]

∴ 27 cartons are needed to pack 3888 soap bars.

Answer:

Number of cardboards in a pile of thickness 44 mm = 16
Number of cardboards in a pile of thickness 1 mm = 1644             
Number of cardboards in a pile of thickness 71.5 cm = 1644×71.5 ×10 = 260         [1 cm=10 mm] 
∴ 260 cardboards will be there in a pile of thickness 71.5 cm.

Page No 133:

Question 12:

Number of cardboards in a pile of thickness 44 mm = 16
Number of cardboards in a pile of thickness 1 mm = 1644             
Number of cardboards in a pile of thickness 71.5 cm = 1644×71.5 ×10 = 260         [1 cm=10 mm] 
∴ 260 cardboards will be there in a pile of thickness 71.5 cm.

Answer:

Height of the flagstaff that casts a shadow of length 8.2 m = 7 m
Height of the building that casts a shadow of length 1 m = 78.2 m                                         
Height of the building that casts a shadow of length 20.5 m = 78.2×20.5 m = 17.5 m
∴ The height of the required building is 17.5 m.

Page No 133:

Question 13:

Height of the flagstaff that casts a shadow of length 8.2 m = 7 m
Height of the building that casts a shadow of length 1 m = 78.2 m                                         
Height of the building that casts a shadow of length 20.5 m = 78.2×20.5 m = 17.5 m
∴ The height of the required building is 17.5 m.

Answer:

Number of men employed to built the 16.25 m long wall = 15
Number of men required to built a 1 m long wall = 1516.25                       

Number of men that should be employed to built a 26 m long wall = 1516.25×26 = 24
∴ 24 men should be employed to build a wall of length 26 m in a day.

Page No 133:

Question 14:

Number of men employed to built the 16.25 m long wall = 15
Number of men required to built a 1 m long wall = 1516.25                       

Number of men that should be employed to built a 26 m long wall = 1516.25×26 = 24
∴ 24 men should be employed to build a wall of length 26 m in a day.

Answer:

Number of patients who can consume 1350 L of milk = 60
Number of patients who can consume 1 L of milk = 601350                                 
Now, number of patients who can consume 1710 L of milk  = 601350×1710 = 76

Hence, 76 patients can be accommodated in the hospital if the monthly ration of milk is raised to 1710 L.

Page No 133:

Question 15:

Number of patients who can consume 1350 L of milk = 60
Number of patients who can consume 1 L of milk = 601350                                 
Now, number of patients who can consume 1710 L of milk  = 601350×1710 = 76

Hence, 76 patients can be accommodated in the hospital if the monthly ration of milk is raised to 1710 L.

Answer:

Weight that would produce an extension of 2.8 cm = 150 g

Weight that would produce an extension of 1 cm = 1502.8 g

Weight that would produce an extension of 19.6 cm = 1502.8×19.6 = 1050 g = 1 kg 50 g            [1 kg = 1000 g]

∴ A weight of 1 kg 50 g would produce an extension of 19.6 cm.



Page No 134:

Question 1:

Weight that would produce an extension of 2.8 cm = 150 g

Weight that would produce an extension of 1 cm = 1502.8 g

Weight that would produce an extension of 19.6 cm = 1502.8×19.6 = 1050 g = 1 kg 50 g            [1 kg = 1000 g]

∴ A weight of 1 kg 50 g would produce an extension of 19.6 cm.

Answer:

48 men can dig a trench in 14 days.
1 man can dig the trench in 14 × 48 days.                                               [less men, more days]
Therefore, 28 men can dig the trench in 14×4828 days = 24 days              [more men, less days]
Hence, 28 men will take 24 days to dig a similar trench.

Page No 134:

Question 2:

48 men can dig a trench in 14 days.
1 man can dig the trench in 14 × 48 days.                                               [less men, more days]
Therefore, 28 men can dig the trench in 14×4828 days = 24 days              [more men, less days]
Hence, 28 men will take 24 days to dig a similar trench.

Answer:

No. of men required to reap the field in 30 days = 16
No. of men required to reap the field in 1 day = 16 ×30                        (less days, more men)
Now, no. of men required to reap the field in 24 days = 16×3024 = 20    (more days, less men)

∴ 20 men are required to reap the field in 24 days.



Page No 135:

Question 3:

No. of men required to reap the field in 30 days = 16
No. of men required to reap the field in 1 day = 16 ×30                        (less days, more men)
Now, no. of men required to reap the field in 24 days = 16×3024 = 20    (more days, less men)

∴ 20 men are required to reap the field in 24 days.

Answer:

Number of cows that can graze the field in 13 days = 45
Number of cows that can graze the field in 1 day = 45 ×13           [Less days, more cows]
Therefore, number of cows that can graze the field in 9 days = 45×139 = 65   [More days, less cows]

Hence, 65 cows can graze the field in 9 days.

Page No 135:

Question 4:

Number of cows that can graze the field in 13 days = 45
Number of cows that can graze the field in 1 day = 45 ×13           [Less days, more cows]
Therefore, number of cows that can graze the field in 9 days = 45×139 = 65   [More days, less cows]

Hence, 65 cows can graze the field in 9 days.

Answer:

Time taken by 16 horses to consume the corn = 25 days
Time taken by 1 horse to consume the corn = 25×16                    [less horses, more time taken]
Time taken by 40 horses to consume the corn = 25×1640= 10 days     [more horses, less time taken]

Hence, 40 horses would consume the same quantity of corn in 10 days.

Page No 135:

Question 5:

Time taken by 16 horses to consume the corn = 25 days
Time taken by 1 horse to consume the corn = 25×16                    [less horses, more time taken]
Time taken by 40 horses to consume the corn = 25×1640= 10 days     [more horses, less time taken]

Hence, 40 horses would consume the same quantity of corn in 10 days.

Answer:

Days taken to finish the book if 18 pages are read everyday = 25
Days taken to finish the book if 1 page is read everyday = 18 ×25                          [less pages, more days]
Now, days taken to finish the book if 15 pages are read everyday = 18×2515 = 30     [more pages, less days]
Hence, the girl will take 30 days to finish the book if she reads 15 pages everyday.

Page No 135:

Question 6:

Days taken to finish the book if 18 pages are read everyday = 25
Days taken to finish the book if 1 page is read everyday = 18 ×25                          [less pages, more days]
Now, days taken to finish the book if 15 pages are read everyday = 18×2515 = 30     [more pages, less days]
Hence, the girl will take 30 days to finish the book if she reads 15 pages everyday.

Answer:

Time taken to type 40 words per minute = 24 min
Time taken to type a word per minute = 24×40 min                      
Now, time taken to type 48 words per minute = 24×4048 = 20 min

Hence, Geeta will take 20 minutes to type the same document if her typing speed is 48 words/min.

Page No 135:

Question 7:

Time taken to type 40 words per minute = 24 min
Time taken to type a word per minute = 24×40 min                      
Now, time taken to type 48 words per minute = 24×4048 = 20 min

Hence, Geeta will take 20 minutes to type the same document if her typing speed is 48 words/min.

Answer:

Time taken to cover the distance at a speed of 45 km/h = 3 h 20 min = 200 min
Time taken to cover the distance at a speed of 1 km/h = 45 × 3.33 min             [less speed, more time]
Time taken to cover the distance at a speed of 36 km/h = 45×3.3336 = 4.1625 h ≈ 4 h 10 min

Hence, the bus will take 4 h 10 min to cover the distance if its speed is 36 km/h.

Page No 135:

Question 8:

Time taken to cover the distance at a speed of 45 km/h = 3 h 20 min = 200 min
Time taken to cover the distance at a speed of 1 km/h = 45 × 3.33 min             [less speed, more time]
Time taken to cover the distance at a speed of 36 km/h = 45×3.3336 = 4.1625 h ≈ 4 h 10 min

Hence, the bus will take 4 h 10 min to cover the distance if its speed is 36 km/h.

Answer:

Time taken to make 240 tonnes of steel = 30 days
Time taken to make 1 tonne of steel = 30 × 240 days
Now, time taken to make 300 or (240 + 60) tonnes of steel = 30×240300 = 24 days

∴ The materials will last for 24 days if 60 more tonnes of steel is to be made that month.

Page No 135:

Question 9:

Time taken to make 240 tonnes of steel = 30 days
Time taken to make 1 tonne of steel = 30 × 240 days
Now, time taken to make 300 or (240 + 60) tonnes of steel = 30×240300 = 24 days

∴ The materials will last for 24 days if 60 more tonnes of steel is to be made that month.

Answer:

Initially, the contractor had 210 men for 60 days. After 12 days, 70 more men joined.

210 men can finish the work in 48 days
1 man can finish the work in 210×48 days
Now, 280 men can finish the work in 210×48280 days = 36 days.

Hence, it will take 36 days to finish the remaining work.

Page No 135:

Question 10:

Initially, the contractor had 210 men for 60 days. After 12 days, 70 more men joined.

210 men can finish the work in 48 days
1 man can finish the work in 210×48 days
Now, 280 men can finish the work in 210×48280 days = 36 days.

Hence, it will take 36 days to finish the remaining work.

Answer:

No. of men for which the provision will last for 25 days = 360
No. of men for which the provision will last for 1 day = 360 ×25
Now, no. of men for which the provision will last for 30 days = 360×2530 = 300

∴ 60 men, i.e., (360 − 300), must be transferred to another camp so that the provision lasts for 30 days.

Page No 135:

Question 11:

No. of men for which the provision will last for 25 days = 360
No. of men for which the provision will last for 1 day = 360 ×25
Now, no. of men for which the provision will last for 30 days = 360×2530 = 300

∴ 60 men, i.e., (360 − 300), must be transferred to another camp so that the provision lasts for 30 days.

Answer:

Number of days for which the food is sufficient for 120 men = 195
Number of days for which food is sufficient for 1 man = 120×195
Number of days for which food is sufficient for 90 men = 120×19590 = 260

Hence, the food will last for 260 days.

Page No 135:

Question 12:

Number of days for which the food is sufficient for 120 men = 195
Number of days for which food is sufficient for 1 man = 120×195
Number of days for which food is sufficient for 90 men = 120×19590 = 260

Hence, the food will last for 260 days.

Answer:

We are given that in a fort, 1200 soldiers had enough food for 28 days.
Let x soldiers left after 4 days, thus, remaining soldiers = 1200 - x
Now, for these remaining soldiers food lasts for 32 days.
As number of soldiers decrease, food lasts long.

Thus, situation after 4 days is
1200×24=1200-x×321200-x=1200×24321200-x=900x=1200 - 900x=300

Thus, 300 soldiers left the fort after 4 days.

 

Page No 135:

Question 1:

We are given that in a fort, 1200 soldiers had enough food for 28 days.
Let x soldiers left after 4 days, thus, remaining soldiers = 1200 - x
Now, for these remaining soldiers food lasts for 32 days.
As number of soldiers decrease, food lasts long.

Thus, situation after 4 days is
1200×24=1200-x×321200-x=1200×24321200-x=900x=1200 - 900x=300

Thus, 300 soldiers left the fort after 4 days.

 

Answer:

(c) 45.6 kg

Weight of the rod of length 4.5 m = 17.1 kg
Weight of the rod of length 1 m = 17.14.5 kg     [less length, less weight]

∴ Weight of the rod of length 12 m = 17.14.5×12 = 45.6 kg       [more length, more weight]

Page No 135:

Question 2:

(c) 45.6 kg

Weight of the rod of length 4.5 m = 17.1 kg
Weight of the rod of length 1 m = 17.14.5 kg     [less length, less weight]

∴ Weight of the rod of length 12 m = 17.14.5×12 = 45.6 kg       [more length, more weight]

Answer:


(d) none of these

0.8 cm represents 8.8 km.

1 cm represents  8.80.8 km.                   

80.5 cm represents 8.80.8×80.5 = 885.5 km.                                                 

Page No 135:

Question 3:


(d) none of these

0.8 cm represents 8.8 km.

1 cm represents  8.80.8 km.                   

80.5 cm represents 8.80.8×80.5 = 885.5 km.                                                 

Answer:

Distance covered in 20 min = 5 km
Distance covered in 1 min = 520 km                                [less time, less distance covered]
Distance covered in 50 min = 520×50 = 12.5 km          [more time, more distance covered]
Hence, Raghu will cover a distance of 12.5 km in 50 minutes.

Thus, the correct option is (c).

Page No 135:

Question 4:

Distance covered in 20 min = 5 km
Distance covered in 1 min = 520 km                                [less time, less distance covered]
Distance covered in 50 min = 520×50 = 12.5 km          [more time, more distance covered]
Hence, Raghu will cover a distance of 12.5 km in 50 minutes.

Thus, the correct option is (c).

Answer:

Number of days for which 500 men have enough food = 24
Number of days for which 1 man has enough food = 24× 500                     [less men, more food]
Number of days for which 800 men have enough food = 24×500800 = 15        [more men, less food]
Hence, the food will last for 15 days after the reinforcement of 300 men.

Thus, the correct option is (d).

Page No 135:

Question 5:

Number of days for which 500 men have enough food = 24
Number of days for which 1 man has enough food = 24× 500                     [less men, more food]
Number of days for which 800 men have enough food = 24×500800 = 15        [more men, less food]
Hence, the food will last for 15 days after the reinforcement of 300 men.

Thus, the correct option is (d).

Answer:

Time taken to fill 45 of a cistern = 1 min
Time taken to fill 1 cistern =54 min
Time taken to fill 15 of a cistern = 54×15=14 min = 15 seconds

Hence, it will take 15 seconds to fill the rest of the cistern.

Thus, the correct option is (b).



Page No 136:

Question 6:

Time taken to fill 45 of a cistern = 1 min
Time taken to fill 1 cistern =54 min
Time taken to fill 15 of a cistern = 54×15=14 min = 15 seconds

Hence, it will take 15 seconds to fill the rest of the cistern.

Thus, the correct option is (b).

Answer:

Number of cows that eat as much as 15 buffaloes = 21
Number of cows that eat as much as 1 Buffalo = 2115
Number of cows that eat as much as 35 buffaloes = 2115×35 = 49
Hence, 49 cows will eat as much as 35 buffaloes.

Thus, the correct option is (a).

Page No 136:

Question 7:

Number of cows that eat as much as 15 buffaloes = 21
Number of cows that eat as much as 1 Buffalo = 2115
Number of cows that eat as much as 35 buffaloes = 2115×35 = 49
Hence, 49 cows will eat as much as 35 buffaloes.

Thus, the correct option is (a).

Answer:

(b) 75 m

Height of the tree that casts a 4 m long shadow = 6 m
Height of the tree that casts a 1 m long shadow = 64  m
∴ Height of the flag pole that casts a 50 m long shadow = 64×50 = 75 m

Page No 136:

Question 8:

(b) 75 m

Height of the tree that casts a 4 m long shadow = 6 m
Height of the tree that casts a 1 m long shadow = 64  m
∴ Height of the flag pole that casts a 50 m long shadow = 64×50 = 75 m

Answer:

8 men finish the work in 40 days.
1 man can finish the work in 8×40 days.                                                 [Less men, more days]
10 men can finish the work in 8×4010 = 32 days.                                      [More men, less days]
∴ If 2 more men join them, the work will be completed in 32 days.

The correct option is (b).

Page No 136:

Question 9:

8 men finish the work in 40 days.
1 man can finish the work in 8×40 days.                                                 [Less men, more days]
10 men can finish the work in 8×4010 = 32 days.                                      [More men, less days]
∴ If 2 more men join them, the work will be completed in 32 days.

The correct option is (b).

Answer:

Number of days taken to reap the field by 16 men = 30 days
Number of days taken to reap the field by 1 man = 30×16 days                            [Less men, more days]
Number of days taken to reap the field by 20 men = 30×1620 = 24 days                [More men, less days]

Hence, 20 men will take 24 days to reap the field.

The correct option is (b).

Page No 136:

Question 10:

Number of days taken to reap the field by 16 men = 30 days
Number of days taken to reap the field by 1 man = 30×16 days                            [Less men, more days]
Number of days taken to reap the field by 20 men = 30×1620 = 24 days                [More men, less days]

Hence, 20 men will take 24 days to reap the field.

The correct option is (b).

Answer:

Time taken to fill the tank by 10 pipes = 24 min
Time taken to fill the tank by 1 pipe = 24 ×10 min                       [Less pipes, more time taken]
Time taken to fill the tank by 8 pipes = 24×108 min = 30 min        [More pipes, less time taken]
Hence, it will take 30 minutes to fill the tank if two pipes go out of order.

The correct option is (c).

Page No 136:

Question 11:

Time taken to fill the tank by 10 pipes = 24 min
Time taken to fill the tank by 1 pipe = 24 ×10 min                       [Less pipes, more time taken]
Time taken to fill the tank by 8 pipes = 24×108 min = 30 min        [More pipes, less time taken]
Hence, it will take 30 minutes to fill the tank if two pipes go out of order.

The correct option is (c).

Answer:

Cost of 72 eggs = Rs 108
Cost of 1 egg = Rs 10872
Cost of 132 eggs = RS 10872×132 = Rs 198

Hence, 132 eggs will cost Rs 198.

The correct option is (d).

Page No 136:

Question 12:

Cost of 72 eggs = Rs 108
Cost of 1 egg = Rs 10872
Cost of 132 eggs = RS 10872×132 = Rs 198

Hence, 132 eggs will cost Rs 198.

The correct option is (d).

Answer:

Time taken by 12 workers to complete the job = 4 h
Time taken by 1 worker to complete the job = 4×12 h
Time taken by 15 workers to complete the job = 4×1215 = 3 h 12 min

Hence, 15 workers will complete the job in 3 h 12 min.

The correct option is (b).

Page No 136:

Question 13:

Time taken by 12 workers to complete the job = 4 h
Time taken by 1 worker to complete the job = 4×12 h
Time taken by 15 workers to complete the job = 4×1215 = 3 h 12 min

Hence, 15 workers will complete the job in 3 h 12 min.

The correct option is (b).

Answer:

500 men had enough food for 24 days.
1 man had enough food for 24×500 days.                          [Less men, more days]
800 men had enough food for 24×500800 = 15 days             [More men , less days]

Hence, the food will now last for 15 days after the reinforcement of 300 men.

The correct option is (a).

Page No 136:

Question 14:

500 men had enough food for 24 days.
1 man had enough food for 24×500 days.                          [Less men, more days]
800 men had enough food for 24×500800 = 15 days             [More men , less days]

Hence, the food will now last for 15 days after the reinforcement of 300 men.

The correct option is (a).

Answer:

(c) 98

No. of rounds around the cylinder of radius 14 cm = 140
No. of rounds around the cylinder of radius 1 cm = 140×14             [Less radius, more rounds]
No. of rounds around the cylinder of radius 20 cm = 140×1420 = 98      [More radius, less rounds]

Hence, the rope makes 98 rounds around the circumference of the cylinder of radius 20 cm.

Page No 136:

Question 15:

(c) 98

No. of rounds around the cylinder of radius 14 cm = 140
No. of rounds around the cylinder of radius 1 cm = 140×14             [Less radius, more rounds]
No. of rounds around the cylinder of radius 20 cm = 140×1420 = 98      [More radius, less rounds]

Hence, the rope makes 98 rounds around the circumference of the cylinder of radius 20 cm.

Answer:

No. of toys made in 23 h = 1
No. of toys made in 1 h = 32
No. of toys made in 713 h = 32×223=11

Hence, the worker will make 11 toys in 713 h.

The correct option is (d).

Page No 136:

Question 16:

No. of toys made in 23 h = 1
No. of toys made in 1 h = 32
No. of toys made in 713 h = 32×223=11

Hence, the worker will make 11 toys in 713 h.

The correct option is (d).

Answer:

Men required to finish the work in 8 days = 10
Men required to finish the work in 1 day = 10×8                                    [More day, less men]
Men required to finish the work in half a day = 10×812= 10×8×2= 160     [Less days, more men]
Hence, 150 (i.e., 160 − 10) men are added to finish the work in half a day.

The correct option is (d).



Page No 137:

Question 1:

Men required to finish the work in 8 days = 10
Men required to finish the work in 1 day = 10×8                                    [More day, less men]
Men required to finish the work in half a day = 10×812= 10×8×2= 160     [Less days, more men]
Hence, 150 (i.e., 160 − 10) men are added to finish the work in half a day.

The correct option is (d).

Answer:

Cost of 8 toys = Rs 192
Cost of 1 toy = Rs 1928 = Rs 24

∴ Cost of 14 toys = 24×14 = Rs 336

Page No 137:

Question 2:

Cost of 8 toys = Rs 192
Cost of 1 toy = Rs 1928 = Rs 24

∴ Cost of 14 toys = 24×14 = Rs 336

Answer:

Distance covered with 15 L of petrol= 270 km
Distance covered with 1 L of petrol = 27015 km

Distance covered with 8 L of petrol= 27015×8 km = 144 km

Page No 137:

Question 3:

Distance covered with 15 L of petrol= 270 km
Distance covered with 1 L of petrol = 27015 km

Distance covered with 8 L of petrol= 27015×8 km = 144 km

Answer:

Cost of 15 envelopes = Rs 11.25
Cost of 1 envelope = Rs 11.2515                   

∴ Cost of 20 envelopes = 11.2515×20 = Rs 15

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Question 4:

Cost of 15 envelopes = Rs 11.25
Cost of 1 envelope = Rs 11.2515                   

∴ Cost of 20 envelopes = 11.2515×20 = Rs 15

Answer:

Number of cows that graze the field in 20 days = 24
Number of cows that graze the field in 1 day = 24×20                             [Less days, more cows]
∴ Number of cows that graze the field in 15 days = 24×2015 = 32 cows        [More days, less cows]

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Question 5:

Number of cows that graze the field in 20 days = 24
Number of cows that graze the field in 1 day = 24×20                             [Less days, more cows]
∴ Number of cows that graze the field in 15 days = 24×2015 = 32 cows        [More days, less cows]

Answer:

Time taken to finish the work by 8 men = 15 h
Time taken to finish the work by 1 man = 8×15 h                             [Less men, more time taken]
∴ Time taken to finish the work by 20 men = 8×1520 h = 6 h    [More men, less time taken]

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Question 6:

Time taken to finish the work by 8 men = 15 h
Time taken to finish the work by 1 man = 8×15 h                             [Less men, more time taken]
∴ Time taken to finish the work by 20 men = 8×1520 h = 6 h    [More men, less time taken]

Answer:

Time taken to fill 45 of the cistern = 1 min

Time taken to fill 1 cistern = 145=54= 1.25 min = 1 min 15 sec
Hence, it will take 1 min 15 sec to fill the empty cistern.

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Question 7:

Time taken to fill 45 of the cistern = 1 min

Time taken to fill 1 cistern = 145=54= 1.25 min = 1 min 15 sec
Hence, it will take 1 min 15 sec to fill the empty cistern.

Answer:

Time taken to cover the distance at a speed of 45 km/h = 3 h 20 min
Time taken to cover the distance at a speed of 1 km/h = 45 × 3.33 h    [Less speed, more time taken]    
(20 min = 0.33 hour)
∴ Time taken to cover the distance at a speed of 50 km/h = 45×3.3350h ≈ 3 h     [More speed, less time taken]

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Question 8:

Time taken to cover the distance at a speed of 45 km/h = 3 h 20 min
Time taken to cover the distance at a speed of 1 km/h = 45 × 3.33 h    [Less speed, more time taken]    
(20 min = 0.33 hour)
∴ Time taken to cover the distance at a speed of 50 km/h = 45×3.3350h ≈ 3 h     [More speed, less time taken]

Answer:

Number of days with enough food for 120 men = 30
Number of days with enough food for 1 man = 30×120                [Less men, more days]
∴ Number of days with enough food for 100 men = 30×120100 = 36         [More men, less days]

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Question 9:

Number of days with enough food for 120 men = 30
Number of days with enough food for 1 man = 30×120                [Less men, more days]
∴ Number of days with enough food for 100 men = 30×120100 = 36         [More men, less days]

Answer:

(c) 644 km
1 cm represents 8 km.
∴ 80.5 cm  represents 8×80.5 = 644 km.

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Question 10:

(c) 644 km
1 cm represents 8 km.
∴ 80.5 cm  represents 8×80.5 = 644 km.

Answer:

(a) 24 days

16 men can reap the field in 30 days.             
1 man can reap the field in 30×16 days.                        [Less men, more days]
∴ 20 men can reap the field in 30×1620 = 24 days            [More men, less days]

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Question 11:

(a) 24 days

16 men can reap the field in 30 days.             
1 man can reap the field in 30×16 days.                        [Less men, more days]
∴ 20 men can reap the field in 30×1620 = 24 days            [More men, less days]

Answer:

(b) 49

Number of cows that eat as much as 15 buffaloes = 21
Number of cows that eat as much as 1 buffalo = 2115            

∴ Number of cows that eat as much as 35 buffaloes = 2115×35 = 49

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Question 12:

(b) 49

Number of cows that eat as much as 15 buffaloes = 21
Number of cows that eat as much as 1 buffalo = 2115            

∴ Number of cows that eat as much as 35 buffaloes = 2115×35 = 49

Answer:

Number of cows that graze the field in 12 days = 45

Number of cows that graze the field in 1 day = 45×12                         
 
∴ Number of cows that graze the field in 9 days = 45×129   = 60

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Question 13:

Number of cows that graze the field in 12 days = 45

Number of cows that graze the field in 1 day = 45×12                         
 
∴ Number of cows that graze the field in 9 days = 45×129   = 60

Answer:

(b) Rs 162

Cost of 72 eggs = Rs 108
Cost of 1 egg =Rs 10872                    

Cost of 108 eggs = Rs 108×10872 = Rs 162

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Question 14:

(b) Rs 162

Cost of 72 eggs = Rs 108
Cost of 1 egg =Rs 10872                    

Cost of 108 eggs = Rs 108×10872 = Rs 162

Answer:

(i) 588 days
42 men can dig the trench in 14 days.
1 man can dig the trench in 14 × 42 days = 588 days

(ii) Rs. 48
15 oranges cost Rs 60.
12 oranges will cost Rs  6015×12 = Rs 48

(iii) 10.8 kg
A rod of length 10 m weighs 18 kg.
A rod of length 6 m will weigh 1810×6 = 10.8 kg

(iv) 3 h 12 min
12 workers finish the work in 4 h.
15 workers will finish the work in 4×1215 = 3.2 h = 3 h 12 min

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Question 15:

(i) 588 days
42 men can dig the trench in 14 days.
1 man can dig the trench in 14 × 42 days = 588 days

(ii) Rs. 48
15 oranges cost Rs 60.
12 oranges will cost Rs  6015×12 = Rs 48

(iii) 10.8 kg
A rod of length 10 m weighs 18 kg.
A rod of length 6 m will weigh 1810×6 = 10.8 kg

(iv) 3 h 12 min
12 workers finish the work in 4 h.
15 workers will finish the work in 4×1215 = 3.2 h = 3 h 12 min

Answer:

(i) F
10 pipes fill the tank in 24 min.
1 pipe will fill the tank in 24 ×10 min.                (Less pipes, more time taken)
8 pipes will fill the tank in 24×108 = 30 min      (More pipes, less time taken)

(ii) T
8 men finish the work in 40 days.
1 man finishes the work in 8×40 days.                  (Less men, more days taken)
10 men will finish the work in 8×4010 = 32 days      (More men, less days taken)

(iii) T
A 6 m tall tree casts a shadow of length 4 m.
A 1 m tall tree cast a shadow of length 46 m.            
A 75 m tall pole will cast a shadow of length 46×75 =50 m

(iv) T
1 toy is made in 23 h.                              (Less toys, less time taken)
12 toys can be made in 23×12 = 8 h      (More toys, more time taken)



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