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(1+x

^{2}+y^{2}+x^{2}y^{2})^{1/2}+ xy dy/dx =0 how to solve dis diffrential equation!?! ..please ans asap!! :)1. Solve diff eqn dy/dx + y cotx = x2 cotx + 2x

2. Find distance of the point (-2 , 3 , -4 ) from the line x + 2/3 = 2y +3/4 = 3z + 4/5 m,easutres II to plane 4x + 12y - 3z +1 =0

how can we solve ; dy/dx=tan 2(x+y) or dy/dx=tan square (x+y)

number chart for maths fair

Solve (1+y

^{2})dx = (tan^{-1}y - x)dyxdy/dx + y = xcosx + sinx given that y (pi/2) = 1

if x=a(t+sint) , y=a(1-cost) , show that y''=1/a , at t=90deegre .(or) pi/2

dy/dx+xsin2y=x

^{3}cos^{2}ySolve the differential equation:

x dy/dx + y = x cosx + sinx

given that y(pie/2) =1.

form the differential equation of a family of circles touching y- axis at origin

Solve:

dy/dx = 1 + x + y + xy

Answer given in the book is : log | 1 + y| = x + 1/2 x

^{2}+ Csolve-

(x

^{2 }+ xy)dy = ( x^{2}+ y^{2})dxSolve:

( 1 + e

^{x/y})dx + e^{x/y}( 1 - x/y) dy = 0The answer given in the book is : x + y e

^{x/y}= C_{1}Show that Ax

^{2}+ By^{2}=1 is a solution of the differential equation x[y( d^{2}y/dx^{2}) + (dy/dx)^{2}] = y dy/dx.Solve:

x ( 1 + y

^{2}) dx - y ( 1 + x^{2}) dy = 0, given that y = 0 when x = 1The answer given in the book is : ( 1 + x

^{2}) = 2 ( 1 + y^{2})^{y/x}=x,then prove that x^{3}d^{2}^{}y/dx^{2}=(xdy/dx-y)^{2.}Solve the differential equation: (tan^-1y- x)dy=(1+y^2)dx

Solve:

cos x cos y dy + sin x sin y dx= 0

The answer give in the book is : sin y = C cos x

Q10. (x-y) dy/dx =x + 2y

^{2})dy/dx+y=e^{tan}^{-1x}Form the differential equation of the family of circles having centre on

y-axis and radius 3 units...... see in this question in ncert values of arbitaray constant is calculated and then put in the given eqn ..... but can it be also done if we jst differentiate the given eqn . because in that also nothing much is changed except the answer !.can the form can have one or more forms ?

^{2}] )^{n , }then show that (1 +x^{2}) d^{2}y /dx^{2 }+ x dy/dx = n^{2}ysec

^{2}x tany dx +sec^{2}y tanx dy=0. Form the differential eqation. plz help meform the differential equation of the family of circles touching the second quadrant

( cos

^{2}x ) dy/dx + y = tan xThe answer: y = tan x – 1 + Ce

^{- tan x}y=sin(log x)prove that

x

^{2}d^{2}y/dx^{2}+dy/dx +y =0x.dy/dx=y(log y-log x - 1)

solve differential equation sqrt 1+x

^{2}+y^{2}+x^{2}y^{2}+ xy dy/dx=0find the differential equation of all the parabolas with latus rectum 4a and whose axes r parallel to x-axis.

^{-1}x, x >1, then show that x(x^{2}-1) d^{2}y/dx^{2 }+ (2x^{2}- 1) dy/dx = 0.solve the differential equation-

x

^{2}dy/dx= 2xy+y^{2}Q1 Verify that y2 =4ax is a solution of the differential equation y= x dy/dx + a dx/dy

Assume that a rain drop evaporates at a rate proportional to its surface . form a differrential equation involving the rate of change of the radius of the rain drop....

ques. To solve the differential equation : y - x.dy/dx=a( y

^{2}+ x^{2}.dy/dx) ; y(a)=a.find the general solution for the above equation .

Solve:

( e

^{y}+ 1) cosx dx + e^{y}sin x dy = 0The answer given in the book is : ( 1 + e

^{y}) sin x = C_{1}x(logx) dy/dx + y =2(logx).......plz help me to how to solve it???????