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1.Find the missing frequency f, if the mode of the given data is 154.
Classes
120-130
130-140
140-150
150-160
160-170
170-180
Frequency
2
8
12
f
9
7
plzz give an answer fast....
10. If median = 15 and mean = 16, find mode of the distribution
what is hit and trial method .
In the step deviation method,
What is the meaning of ui ?
If the median of the distribution is given below is 28.5, find the values of x and y.
Class interval
0 − 10
5
10 − 20
x
20 − 30
20
30 − 40
15
40 − 50
y
50 − 60
Total
60
if the median of the following frequency distribution is 24. find the missing frequency x :
Age Number of persons
0 - 10 5
10 - 20 25
20 - 30 x
30 - 40 18
40 - 50 7
In statistics Ex 14.1 Q8 of class 10..if we solve the question by using step deviation, what value of h willwe take as in the book it is written that if the class sizes areunequal, and xi are large numerically we can still apply stepdeviation method taking h to be a suitable divisor of all the di "But in Example 3 of statistics we have taken h to be 20 whereas it isnot a divisor to all the di's. It is not a divisor to -75...Please explain this to me
find the missing frequencies if N=100 and median is 32.
marks obtained-0-10, 10-20, 20-30, 30-40, 40-50, 50-60, total
no. of students-10 ,? ,25 ,30 ,? ,10 ,100.
monthly consumption of electricity of some consumers is given below as a distribution. Find the missing frequency(x), if mode is given to be 200 units.
Monthly cosumption(in units ) 90-120 120-150 150-180 180-210 210-240
Number of consumers 20 15 X 75 30
The median of the following distribution is 30. Find the missing frequencies f1 and f2:
Class frequency
0-10 10
10-20 10
20-30 f1
30-40 30
40-50 f2
50-60 10
Total 100
how to calculate mode if two classes have same and highest frequency (bimodal) ?
the mean of 10 numbers is 20.if 5 is subtracted from every number.what will be the new mean?
IF THE N/2 IS EQUAL TO THE CUMULATIVE FREQUENCY THEN WE WOULD REGARD THAT CLASS AS THE MEDIAN CLASS OR NOT.
how to find the mean if the class intervals are unequal??
like fr e- 0-10,10-30,30-35....
The mean of 25 observations is 9 . if each observation is increased by 4 then the new mean is _______
The following table shows the distribution of some families according to expenditure per week .the number of families for two class intervalsare missing. Median =Rs.25 , Mode = Rs.24. calculate the missing frequency and hence the find mean.
how to find xi?
1. Observe the information's in the following cumilative frequency table
no. of days absent
less than 5
less than 10
less than 15
less than 20
less than 25
less than 30
less than 35
less than 40
less than 45
No. of students
29
224
465
582
634
644
650
653
655
Q.. Draw a 'less than' ogive and 'more than' ogive to represent the above data .
Q... Find median for the above data by interpreting the graph.
Q...why regularity is essential in students life (VBQ)
What is the formula to use median when more than ogive is given?
if the median salary of 100 employees of a factory is 24800, then find the missing frequencies f1
and f2 in the given data
Salary 10000-15000 15000-20000 20000-25000 25000-30000 30000-35000 35000-40000
frequen. 18 f1 f2 15 12 22
A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent.
Number of days
0 − 6
6 − 10
10 − 14
14 − 20
20 − 28
28 − 38
38 − 40
Number of students
11
10
4
3
1
3 Median = Mode + 2 Mean
please proof it.
In a continuous frequency distribution, the median of the data is 21.If each observation is increased by 5 find the new median
The mean and median of same data are 24 and 26 respectively. The value of mode is ?
in a grouped frequency distribution,the class with the maximum frequency is called?
a.mean class b.median class c.modal class d.distribution class
The following distribution gives the daily income of 50 workers of a factory.
Daily income (in Rs)
100 − 120
120 − 140
140 − 160
160 − 180
180 − 200
Number of workers
14
6
Convert the distribution above to a less than type cumulative frequency distribution, and draw its ogive.
calculate the aritemetic mean,for the following frequency distribution
class interval frequency
0-80 22
80-160 35
160-240 44
240-320 25
320-400 24
Find the value of f1 from the following data if it's mode is 65:
0-20 6
20-40 8
40-60 f1
60-80 12
80-100 6
100-120 5
Where frequency 6,8, f1, and 12 are in ascending order.
Calculate the mean, median and mode of the following frequency
the mean of first n odd natural numbers is n2/81,then n=
if the mean of the following frequency distribution is 91, find the missing frequency x and y :
classes frequency
0 - 30 12
30-60 21
60 - 90 x
90 -120 52
120 - 150 y
150 - 180 11
total 150
.Find the median when mean = 20 and mode = 18.is it 19.3 cm ?
The mean of n observations is X . IF the first item is increased by 1, second by 2 and so on, then the new mean is:
1. X+n
2. X+n/2
3. X+(n+1)/2
4. X+(n-1)/2
If median salary of 100 employees of a factory isrupees 24800, the find the missing frequencies f1 and f2 in the given distribution table: Salary 10000- 15000- 20000- 25000- 30000- 35000- (In Rupees) 15000 20000 25000 30000 35000 40000 Number 18 f1 f2 15 12 22 of employees
the interest paid on each of the three different sums of money yeilding 1%, 2% and 4% simple interest per annum respectively, is the same. find the average yield percent on the total sum inverted.
how do we find mean using step deviation method if the classes are unequal?
should we make the classes equal in such a case?
During the medical check-up of 35 students of a class, their weights were recorded as follows:
Weight (in kg)
Less than 38
0
Less than 40
Less than 42
Less than 44
Less than 46
Less than 48
28
Less than 50
32
Less than 52
35
Draw a less than type ogive for the given data. Hence obtain the median weight from the graph verify the result by using the formula.
Find the sum of deviations of the variate values 3, 4, 6, 7, 8, 14 fromtheir mean.
The median of the following incomplete frequency distribution is 4 :
x= 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8
f= 2 , 3 , 4 , 1 , 2 , 4 , 2 , x
the frequency of 8 is : A) 1 B) 2 C) 3 D) 4 plz ans fastt....
the median of the data is 525. find x and y, if total frequency is 100
class 0-100 100-200 200-300 300-400 400-500 500-600 600-700 700-800 800-900 900-1000
frequeency 2 5 x 12 17 20 y 9 7 4
classes
0-10
10-20
20-30
30-40
40-50
frequency
k
If the mean of the following data is 21.5 find the value of k
9. If the mean of the distribution is 57.6 and the sum of its observations is 50, find the missing
The mean of the following frequency dristibution is 50. Find the value of p
In a school 85 boys and 35 girls appeared in a public examination . The mean marks of the boys were found to be 40 % whereas the mean marks of the girls were 60% . Determine the average marks % of the school.
in a health check up , the nuber of heart beats of 40 women were recorded in the following table: -no.of heart beats per minute | 65-69 | 70-74 | 75-79 | 79-84 | - no of women | 2 | 18 | 16 | 4 | find the mean of the data.
how can we find the median by only less than ogive curve?
The median of the following data is 32.5.find the value of x and y
class interval f
0-10 x
10-20 5
20-30 9
30-40 12
40-50 y
50-603
60-70 2
total 40
The following table shows the marks obtained by 100 students of class X in a school during a particular academic session. Find the mode of this distribution.
Marks No. of students
Less than 10 7
Less than 20 21
Less than 30 34
Less than 40 46
Less than 50 66
Less than 60 77
Less than 70 92
Less than 80 100
Find the mean, mode and median for the following data.
The mean of the following data is 38.2. Find the missing frequencies f1 and f2 if the total frequency is 50.
50-60
60-70
F1
F2
The median of the following data is 20.75. Find the missing frequencies x and y, if the total frequency is 100.
Class interval:-0-5 5-10 10-15 15-20 20-25 25-30 30-35 35-40
Frequencies: -7 10 x 13 y 10 14 9
the followind data shows the number of toys in a group of 30 children find the median
numbr of toys = 0-2, 2-4, 4-6, 6-8
number of children= 1 , 10 , 12 , 7
how to find the median class?
How to find missing frequency if the mode of the given data is given.
How to convert a LESS THAN OGIVE and it's CF into the Frequency distribution?
Find the class marks of classes 10 - 25 and 35 - 55.
1.Form an ordinary frequency distribution table from the following CF distribution table and calculate mean, median and mode + median ogive.
20-30 2
30-40 0
40-50 4
50-60 3
60-70 6
70-80 0
80-90 4
90-100 10
If the less than ogive and more than ogive intersect each other at ( 20.5,15.5 ), then the median of the given data is :
A ) 36.0 B) 20.5 C ) 15.5 D ) 5.5
If the mean of the following distributions is 27, Find the value of p
The mean of the following data is 53, find the missing frequencies.
age in years -- 0-20, 20-40 40-60 60-80, 80-100
number of people--- 15, f1, 21, f2, 17, 100
the class mark of classes in a distribution arer 6.10.14.18.22.26.30. find
a) class size
b) lower limit of second class
c) upper lmit of last class
d) third class
E.g: 9876543210, 01112345678
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Syllabus
1.Find the missing frequency f, if the mode of the given data is 154.
Classes
120-130
130-140
140-150
150-160
160-170
170-180
Frequency
2
8
12
f
9
7
plzz give an answer fast....
10. If median = 15 and mean = 16, find mode of the distribution
what is hit and trial method .
In the step deviation method,
What is the meaning of ui ?
If the median of the distribution is given below is 28.5, find the values of x and y.
Class interval
Frequency
0 − 10
5
10 − 20
x
20 − 30
20
30 − 40
15
40 − 50
y
50 − 60
5
Total
60
Q. 27. School held sports day in which 150 students participated. Age of students are given in the following frequency distribution;
(in years)
For the above data, draw a more than type, ogive and from the curve, find median. Verify it by actual calculations.
if the median of the following frequency distribution is 24. find the missing frequency x :
Age Number of persons
0 - 10 5
10 - 20 25
20 - 30 x
30 - 40 18
40 - 50 7
In statistics Ex 14.1 Q8 of class 10..
if we solve the question by using step deviation, what value of h will
we take as in the book it is written that if the class sizes are
unequal, and xi are large numerically we can still apply step
deviation method taking h to be a suitable divisor of all the di "
But in Example 3 of statistics we have taken h to be 20 whereas it is
not a divisor to all the di's. It is not a divisor to -75...
Please explain this to me
find the missing frequencies if N=100 and median is 32.
marks obtained-0-10, 10-20, 20-30, 30-40, 40-50, 50-60, total
no. of students-10 ,? ,25 ,30 ,? ,10 ,100.
monthly consumption of electricity of some consumers is given below as a distribution. Find the missing frequency(x), if mode is given to be 200 units.
Monthly cosumption(in units ) 90-120 120-150 150-180 180-210 210-240
Number of consumers 20 15 X 75 30
The median of the following distribution is 30. Find the missing frequencies f1 and f2:
Class frequency
0-10 10
10-20 10
20-30 f1
30-40 30
40-50 f2
50-60 10
Total 100
how to calculate mode if two classes have same and highest frequency (bimodal) ?
the mean of 10 numbers is 20.if 5 is subtracted from every number.what will be the new mean?
IF THE N/2 IS EQUAL TO THE CUMULATIVE FREQUENCY THEN WE WOULD REGARD THAT CLASS AS THE MEDIAN CLASS OR NOT.
how to find the mean if the class intervals are unequal??
like fr e- 0-10,10-30,30-35....
The mean of 25 observations is 9 . if each observation is increased by 4 then the new mean is _______
The following table shows the distribution of some families according to expenditure per week .the number of families for two class intervalsare missing. Median =Rs.25 , Mode = Rs.24. calculate the missing frequency and hence the find mean.
how to find xi?
1. Observe the information's in the following cumilative frequency table
no. of days absent
less than 5
less than 10
less than 15
less than 20
less than 25
less than 30
less than 35
less than 40
less than 45
No. of students
29
224
465
582
634
644
650
653
655
Q.. Draw a 'less than' ogive and 'more than' ogive to represent the above data .
Q... Find median for the above data by interpreting the graph.
Q...why regularity is essential in students life (VBQ)
PLEASE ANSWER FAST.
What is the formula to use median when more than ogive is given?
Class Interval
20-30
30-40
40-50
50-60
60-70
Frequency
25
47
62
p
10
median.
Classes 20-30 30-40 40-50 50-60 60-70 70-80 80-90
frequency 10 8 12 24 6 25 15
if the median salary of 100 employees of a factory is 24800, then find the missing frequencies f1
and f2 in the given data
Salary 10000-15000 15000-20000 20000-25000 25000-30000 30000-35000 35000-40000
frequen. 18 f1 f2 15 12 22
A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent.
Number of days
0 − 6
6 − 10
10 − 14
14 − 20
20 − 28
28 − 38
38 − 40
Number of students
11
10
7
4
4
3
1
Marks Below 10 Below 20 Below 30 Below 40 Below 50 Below 60 Below 70 Below 80 Below 90 Below 100
No. of students 5 9 17 29 45 60 70 78 83 85
3 Median = Mode + 2 Mean
please proof it.
20-40
40-60
60-80
80-100
17
f1
f2
f3
19
In a continuous frequency distribution, the median of the data is 21.If each observation is increased by 5 find the new median
The mean and median of same data are 24 and 26 respectively. The value of mode is ?
in a grouped frequency distribution,the class with the maximum frequency is called?
a.mean class b.median class c.modal class d.distribution class
marks number of students
0 and above 80
10 and above 77
20 and above 72
30 and above 65
40 and above 55
50 and above 43
60 and above 28
70 and above 16
80 and above 10
90 and above 8
100 and above 0
family size:0-4,4-8,8-12,12-16,16-20
number of families:8,14,12,4,2
find median and mode.
The following distribution gives the daily income of 50 workers of a factory.
Daily income (in Rs)
100 − 120
120 − 140
140 − 160
160 − 180
180 − 200
Number of workers
12
14
8
6
10
Convert the distribution above to a less than type cumulative frequency distribution, and draw its ogive.
calculate the aritemetic mean,for the following frequency distribution
class interval frequency
0-80 22
80-160 35
160-240 44
240-320 25
320-400 24
Find the value of f1 from the following data if it's mode is 65:
Class frequency
0-20 6
20-40 8
40-60 f1
60-80 12
80-100 6
100-120 5
Where frequency 6,8, f1, and 12 are in ascending order.
Calculate the mean, median and mode of the following frequency
distribution:Classintervals:15 - 20 20 - 25 25 - 30 30 - 35 35 - 40 40 45 45 - 50 50 55Frequency: 3 8 9 10 4 3 2 1Draw the less than and more than O give (Cumulative Frequency Curve) for theabove data and hence find the median.the mean of first n odd natural numbers is n2/81,then n=
In a school , IQ of 250 students of class 10 are given in the following frequency distribution
IQ 120-130 130-140 140-150 150-160 160-170
no.10 80 100 50 10. Find the mean IQ of students .
of
students
if the mean of the following frequency distribution is 91, find the missing frequency x and y :
classes frequency
0 - 30 12
30-60 21
60 - 90 x
90 -120 52
120 - 150 y
150 - 180 11
total 150
.Find the median when mean = 20 and mode = 18.is it 19.3 cm ?
The mean of n observations is X . IF the first item is increased by 1, second by 2 and so on, then the new mean is:
1. X+n
2. X+n/2
3. X+(n+1)/2
4. X+(n-1)/2
If median salary of 100 employees of a factory isrupees 24800, the find the missing frequencies f1 and f2 in the given distribution table:
Salary 10000- 15000- 20000- 25000- 30000- 35000-
(In Rupees) 15000 20000 25000 30000 35000 40000
Number 18 f1 f2 15 12 22
of employees
class frequency
40-50 5
50-60 x
60-70 15
70-80 2
80-90 7
the interest paid on each of the three different sums of money yeilding 1%, 2% and 4% simple interest per annum respectively, is the same. find the average yield percent on the total sum inverted.
how do we find mean using step deviation method if the classes are unequal?
should we make the classes equal in such a case?
Compute the median from the data
mid value 115 125 135 145 155 165 175 185
frequency 6 25 48 72 116 60 38 22
During the medical check-up of 35 students of a class, their weights were recorded as follows:
Weight (in kg)
Number of students
Less than 38
0
Less than 40
3
Less than 42
5
Less than 44
9
Less than 46
14
Less than 48
28
Less than 50
32
Less than 52
35
Draw a less than type ogive for the given data. Hence obtain the median weight from the graph verify the result by using the formula.
Class interval Frequency
0-10 10
10-20 20
20-30 x
30-40 40
40-50 y
50-60 25
60-70 15
Find the sum of deviations of the variate values 3, 4, 6, 7, 8, 14 from
their mean.
Class interval Frequency
10-20 12
20-30 30
30-40 f1
40-50 65
50-60 f2
60-70 25
70-80 18
no links plz.
The median of the following incomplete frequency distribution is 4 :
x= 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8
f= 2 , 3 , 4 , 1 , 2 , 4 , 2 , x
the frequency of 8 is : A) 1 B) 2 C) 3 D) 4 plz ans fastt....
the median of the data is 525. find x and y, if total frequency is 100
class 0-100 100-200 200-300 300-400 400-500 500-600 600-700 700-800 800-900 900-1000
frequeency 2 5 x 12 17 20 y 9 7 4
classes
0-10
10-20
20-30
30-40
40-50
frequency
6
4
3
k
2
If the mean of the following data is 21.5 find the value of k
classes
0-10
10-20
20-30
30-40
40-50
frequency
6
4
3
k
2
If the mean of the following data is 21.5 find the value of k
classes
0-10
10-20
20-30
30-40
40-50
frequency
6
4
3
k
2
If the mean of the following data is 21.5 find the value of k
classes
0-10
10-20
20-30
30-40
40-50
frequency
6
4
3
k
2
If the mean of the following data is 21.5 find the value of k
classes
0-10
10-20
20-30
30-40
40-50
frequency
6
4
3
k
2
If the mean of the following data is 21.5 find the value of k
9. If the mean of the distribution is 57.6 and the sum of its observations is 50, find the missing
The mean of the following frequency dristibution is 50. Find the value of p
Class Interval 0-10 10-20 20-30 30-40 40-50 50-60 60-70 70-80 80-90 90- 100
frequency 2 5 X 12 17 20 Y 9 7 4
In a school 85 boys and 35 girls appeared in a public examination . The mean marks of the boys were found to be 40 % whereas the mean marks of the girls were 60% . Determine the average marks % of the school.
in a health check up , the nuber of heart beats of 40 women were recorded in the following table:
-no.of heart beats per minute | 65-69 | 70-74 | 75-79 | 79-84 |
- no of women | 2 | 18 | 16 | 4 |
find the mean of the data.
how can we find the median by only less than ogive curve?
Classes Frequency
0-5 7
5-10 6
10-15 f
15-20 4
20-25 3
a) f <8
b) f >8
c) f > 8 only
d) f<7
The median of the following data is 32.5.find the value of x and y
class interval f
0-10 x
10-20 5
20-30 9
30-40 12
40-50 y
50-603
60-70 2
total 40
The following table shows the marks obtained by 100 students of class X in a school during a particular academic session. Find the mode of this distribution.
Marks No. of students
Less than 10 7
Less than 20 21
Less than 30 34
Less than 40 46
Less than 50 66
Less than 60 77
Less than 70 92
Less than 80 100
Find the mean, mode and median for the following data.
The mean of the following data is 38.2. Find the missing frequencies f1 and f2 if the total frequency is 50.
Classes
0-10
10-20
20-30
30-40
40-50
50-60
60-70
Frequency
4
4
F1
10
F2
8
5
The median of the following data is 20.75. Find the missing frequencies x and y, if the total frequency is 100.
Class interval:-0-5 5-10 10-15 15-20 20-25 25-30 30-35 35-40
Frequencies: -7 10 x 13 y 10 14 9
the followind data shows the number of toys in a group of 30 children find the median
numbr of toys = 0-2, 2-4, 4-6, 6-8
number of children= 1 , 10 , 12 , 7
Q. If the mean of the following frequency distribution is 65.6. Find the missing frequency F1 and F2 .
how to find the median class?
C.I. F
45-55 7
55-65 12
65-75 17
75-85 30
85-95 32
95-105 6
105-115 10
How to find missing frequency if the mode of the given data is given.
Daily wage 200-300 , 300-400 , 400-500 , 500-600 , 600-700 , 700-800
number of workers 16 , X ,17, 20, 15, Y
Please reply fast........
How to convert a LESS THAN OGIVE and it's CF into the Frequency distribution?
Find the class marks of classes 10 - 25 and 35 - 55.
1.Form an ordinary frequency distribution table from the following CF distribution table and calculate mean, median and mode + median ogive.
class interval frequency
20-30 2
30-40 0
40-50 4
50-60 3
60-70 6
70-80 0
80-90 4
90-100 10
29
If the less than ogive and more than ogive intersect each other at ( 20.5,15.5 ), then the median of the given data is :
A ) 36.0 B) 20.5 C ) 15.5 D ) 5.5
If the mean of the following distributions is 27, Find the value of p
CLASS FREQUENCY
0-10 5
10-20 x
20-30 20
30-40 14
40-50 y
50-60 8
TOTAL 68
The mean of the following data is 53, find the missing frequencies.
age in years -- 0-20, 20-40 40-60 60-80, 80-100
number of people--- 15, f1, 21, f2, 17, 100
Total = 50
height in cm frequency cumulative frequency
150-155 12 a
155-160 b 25
160-165 10 c
165-170 d 43
170-175 e 48
175-180 2 f
the class mark of classes in a distribution arer 6.10.14.18.22.26.30. find
a) class size
b) lower limit of second class
c) upper lmit of last class
d) third class