Zn +NaOH +NaNo3 -------- Na2ZnO2 +NH3 +H2O balance the equation

Solution:
The chemical equation is

 

Zn + NaNO3 + NaOH = Na2ZnO2 + NH3 + H2O

 

Zn is oxidized to Zn(+2) and N(+5) in NO3 is reduced to N(-3) in NH3. However the oxidation state of sodium remains the same on both sides. Therefore, zinc is reducing agent while NO3- is oxidizing agent in reaction and the changes are shown as:

 

0  +1 +5  +1  2(+1)(+2)  (-3) 

Zn + NaNO3 + NaOH = Na2ZnO2 + NH3 + H2O

 

The increase/decrease in oxidation number ration of Zn to NO3- is 1:4. Hence, balance by multiplying NO3- by 1 and Zn by 4. We get,

 

4 Zn + NaNO3 + NaOH = 4 Na2ZnO2 + NH3 + H2O

 

Now look at the sodium atoms it is 8 on product side, hence to balance it we need to add 7 to NaOH as we should not disturb NO3 with Na (i.e NaNO3) on reactant side. Then the equation becomes,

 

 4 Zn + NaNO3 + 7 NaOH = 4 Na2ZnO2 + NH3 + H2O

 

All other atoms except hydrogen and oxygen are balanced. Now check the equation to balance H and O. They are also balanced. Hence the balanced equation is:

 

4 Zn + NaNO3 + 7 NaOH = 4 Na2ZnO2 + NH3 + 2 H2O

 

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