Write the MO configuration of the following species-
O2 , O2+ , O2- , O22-
Arrange them in order of their decreasing stabilities?
The electronic configuration for O is given as:
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O-atom : 1s 2 2s 2 2p 4
The molecular orbital configuration for O2 molecule can be given as: -
O2 : (σ1s)2 (σ*1s)2 (σ2s)2 (σ*2s)2 (σ2pz )2 (2px2 = 2py2)(2px1=2py1)
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Bond order
O2+ will form by removal of 1 electron from O2.The electron will be removed from 2px or 2py orbital.Bond order in O2 + = 10-5/2= 2.5
Bond order in O2 - = 10-7/2 = 1.5
Bond order in O22- = 10-8/2 = 1So Order of bond order in all four species will be in order : O22-< O2- <O2 < O2+
Maximum the bond order, maximum will be stability.
So the stability order of given species will be O2+ > O2 > O2 - >O22-