write the dimensions of a/b in the relation F=a root x +bt^{2} where F is force , x is distance and t is time. Share with your friends Share 14 Jyoti Pant answered this According to the principle of homogeneity,dimensions of every term on R.H.S should be same as that on L.H.S. i.e force. 75 View Full Answer Nitin Gupta answered this F=a root x +bt^{2}So, dimension of F = a root xm / (s^{2}) = a root (metre)So a = m / (s^{2}) divided by root(metre)Squaring both sides and solving we get--a^{2} = m / s^{4 }-- equation 1stNowdimension of F = dimension of bt^{2}Solve it and you will get b^{2 }= m^{2} / s^{8 }-- equation 2Now divide equation 2 by qyou will get --a / b = s^{4} / mSo converting in dimensions a / b = L ^{-1} T ^{-4}Thanks hope you understood it -12 Shalini Sharma answered this THNX NITIN.. ND YES..I UNDERSTOOD IT.. THNX A LOT.. 0 Senthil Kumar answered this MLT^-2=aL^1/2MLT^-2/L^1/2-=aML^1/2L^1/2T^-2/L1/2=aML^1/2T^-2MLT^-2=bT^2MLT^-2/T^2=BMLT^-4=Ba/b=ML1/2T^-2/MLT^-4 =ML^1/2T^-2/ML^1/2L^1/2T^-4 =L^-1/2T^2 -2