WITHOUT USING TRIGONOMETRIC TABLE,PROVE-
sin 5 tan 22 sec 60 tan 68 sec 85 = 2
Dear Student!
Here is the answer to your question.
sin5⁰ tan22⁰ sec60⁰ tan 68⁰ sec85⁰
= sin5⁰ tan22⁰ sec60⁰ tan (90⁰ - 22⁰) sec (90⁰ - 5⁰)
= sin5⁰ tan22⁰ × 2 × cot 22⁰ cosec5⁰ [ tan(90 - θ)= cot θ, sec(90 - θ)= cosec θ]
= 1 × 1 × 2
= 2
Cheers!