without using the trigonometry table, solve: 3 cos 68. sec 68- tan 43. tan 47. tan 60. tan 12. tan 78 answer fast plz Share with your friends Share 1 Ruba Balu answered this This is hw u must do it. Hope u understood. And plssss give a thumbs up!!!!! 4 View Full Answer Samiksha Sahu answered this 3-root3 1 Crazydrummer answered this 3 cos 68. sec 68 - tan 43. tan 47. tan 60. tan 12. tan 78 = 3 cos 68.1/cos 68 - tan 43. tan(90 - 47) .tan 60. tan 12. tan(90 - 78) = 3*1 - tan 43. tan 43 .tan 60. tan 12. tan 12 = 3 - tan243 . tan 60. tan212 That's all I can do. -1 Loukika Neve answered this The answer is coming 3-root3 -1 Ashwin Gupta answered this 3-√3 0
