without expanding the dterminant show that

1/a a2 bc

1/b b2 ca

1/c c2 ab

=0

frm frst row take a common frm scnd take b frm thrd take c ur det will bcum

1 a bc/a

1 b ac/b

1 c ab/c

and abc common

transform

r1-->r1-r2; r2-->r2-r3

det will bcum

0 a-b bc/a-ac/b

0 b-c ac/b-ab/c

1 c ab/c

wid abc common

now expand along c₁ to get zero..........