# which term of the ap 3,10,17 will be 84 more than its 13th term?

Given A.P. is 3, 10, 17....

Here, a = 3

d = 10 – 3 = 7 Let the term which is 84 more than its 13th term be am. Thus, the required term is 25th term of the given A.P.

• 77

a=3

d=7

a13=a+(13-1)7

=87

THe term 84 more is 87+84=171

171=a+(n-1)d

n=15

tus the aanswer is 15th term

hope it  helps you

• -2

let the nth term be 84 more than the 13 th ter.

now a/q,

a=3

d=10-3=7

so,

13th term= a+12d

=3+12*7

=87

then nth term=84+87=171

171=a+(n-1)d

171=3+(n-1)*7

171-3/7+1=n

168/7+1=n

29=n

therfore 29th term of the ap will be 84 more than 13th term

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• -5

dude,n is wrng...it is 25,not 29...

• -3

a = 3

d= 7

a13 = a + 12d

= 3 + 84

= 87

hence, 87+ 84

= 171

an= 3 + 7n -7

171 = 7n - 4

7n = 175

n = 25

• 16

25

• -3

the term = 84 + a + 12d

= 84 +3+13x7

84+3+84

171

this means that a + (N-1)d = 171

3+ (n-1)7= 171

3 +7n - 7 = 171

7n  - 4 = 171

n = 175/7

= 25

the answer is 25!

• 10
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