Which is greater? and why?
2?13 or 6?2

Solution :

$$\begin{gathered} \text{Assuming the given numbers as : 2}\sqrt{13} and 6\sqrt{2} \\ Now, 2\sqrt{13} = \sqrt{2^2\times 13} = \sqrt{52} \\ Now, 6\sqrt{2} = \sqrt{6^2\times 2} = \sqrt{72} \\ Now, 72 > 52 \\ \Rightarrow \sqrt{72} > \sqrt{52} \\ \Rightarrow 6\sqrt{2} > 2\sqrt{13} \end{gathered}$$

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