When the temperature of certain sample of a gas is changed from 30oC to 606 K and its pressure is reduced to half, the volume of gas changes from V to V2. The value of V is:-


a) 2 dm3
b) 4 dm3
c) 8 dm3
d) Unpredictable

Dear user,
Formula used :
P1V1T1=P2V2T2Here P1=P          P2=P2          V1=V          V2=V2          T1=30C=303K          T2=606KSubstituting the values,we getPV303=PV22×606   V=4dm3
Hence option b is correct.

  • 23
 I  got the answer that is = 4 dm3 , by using the formula P1V1/T1=P2V2/T2. I just did calculation error.
  • 8
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