When ethyl alcohol and acetic acid mixed together in equimolar proportions,equilibrium is attained when two-thirds of the acid and alcohol are consumed.the equilibrium constant for the reaction will be ?

Dear student,
                               CH₃COOH   +  C₂H₅OH     ⇌   CH₃COOC₂H₅    +     H₂O
                                 1 mole              1mole                    0                           0
at ebbm :                  1 - 2/3             1 - 2/3                    2/ 3                       2 /3
 $$\begin{gathered} K_C = \frac{\left[C{H}_{3}COO{C}_2{H}_5\right] \left[H_{2}O\right]}{\left[C{H}_{3}COOH\right] \left[C_2{H}_{5}OH\right]} \\ = \frac{2/3 \times 2/3}{1/3\times 1/3} \end{gathered}$$
             =   4 
Regards