When an object is placed at a distance of 50 cm from a concave mirror , the magnification produced is - 1/2 . where should the object be placed to get a magnification of -1/5
Let, focal length be f.
Now,
Object distance, u = -50 cm
Magnification, m = -1/2
Image distance = v
So, -v/u = -1/2
=> v = u/2 = -25 cm
So,
1/f = 1/v + 1/u
=> 1/f = -1/25 – 1/50
=> f = -50/3 cm
Now,
Magnification is, m = -1/5
So, -v/u = -1/5
=> v = u/5
Thus,
1/f = 1/v + 1/u
=> -3/50 = 5/u + 1/u
=> -3/50 = 6/u
=> u = -100 cm
So, the object must be placed at a distance 100 cm from the mirror.