What should be the width of each slit to obtain maxima of the double slit interference pattern within the central maximum of single slit diffraction pattern? Can you explain it

Solution:
the slit width-wavelength relation is given as     aθ = λ  where   a is the slit width  θ is the angular separation  and  λ is the wavelength     so,  θ = λ/a     now, in this case we have  width of  each slit = width of double maxima  so,  2(λ/d) = 2(λ/a)  or  a = d

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