what must be subtracted from 8x4+14x3-2x2+7x-8 so that the resulting polynomial is exactly divisible by 4x2+3x-2.

Remainder = 14x – 10

∴ 14x – 10 must be subtracted from 8x4 + 14x3 – 2x2 + 7x – 8 so that the resulting polynomial is exactly divisible by 4x2 + 3x – 2.

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14x + 10...when we divise the expression with 4x2 + 3x - 2 , this is the remainder and for an expression to be exactly divisible,the result should b 0.

to make it zero we'll have  to first divide and the remainder ie.14x + 10 is our result.

hope it helps...and i guess my answer is right

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