what is the probability that a leap year has 53 sundays and 53 mondays?
Praveen Philip answered this
53/ 366 and 53/ 366
- -11
amanjain97 answered this
it will be 2/7 and 2/7
- -1
Aishwarya answered this
- leap year has 366 days which is 52 weeks + 2 days there can be 53 sundays only when the last 2 days are
- (saturday , sunday or sunday monday) so P(53 sundays)= 2/7 as total there can be 7 cases similarly P(53 mondays) = 2/7 P(53 sundays or 53 mondays)= P(53 sundays union 53 mondays)
- = P(53 sundays)+ P(53 mondays) - P(53 sundays and 53 mondays) which is seen in only 1 case so P(53 sundays or 53 mondays)
- = 2/7+2/7-1/7 = 3/7
- 10
Parushi answered this
2/7
- 2
Sonu answered this
366 days = 52 weeks + 2 days
2 days can be MT, TW, WT, TF, SS , SM =7
P=2/7
HOPE U UNDERSTAND .................
- 1
Noureesha Noushad answered this
for a NON leap year: No of days = 365
No of week = 52Week +1 day
so first 52weeks will surely have a monday.
Event that a Monday will come on the remaining 1 day: n(E) = 1 [E= {Monday}]
Sample Space (no of Possibilities) n(S) = 7 [ S= {M,T,W,T,F,S,S} ]
Therefore P= n(E)/n(S) = 1/7
for a Non leap year: No of days = 366
No of week = 52Week + 2 days
so first 52weeks will surely have a monday.
Event that a Monday will come on remaining 2 days: n(E) = 2 [E = { (Sun,Mon) / (Mon,Tue) } ]
Sample Space (no of Possibilities) n(S) = 7
[S= { (Sun,Mon) (Mon,Tue) (Tue,Wed) (Wed,Thu) (Thu,Fri) (Fri,Sat) (Sat,Sun) }
Therefore P= n(E)/n(S) = 2/7..
No of week = 52Week +1 day
so first 52weeks will surely have a monday.
Event that a Monday will come on the remaining 1 day: n(E) = 1 [E= {Monday}]
Sample Space (no of Possibilities) n(S) = 7 [ S= {M,T,W,T,F,S,S} ]
Therefore P= n(E)/n(S) = 1/7
for a Non leap year: No of days = 366
No of week = 52Week + 2 days
so first 52weeks will surely have a monday.
Event that a Monday will come on remaining 2 days: n(E) = 2 [E = { (Sun,Mon) / (Mon,Tue) } ]
Sample Space (no of Possibilities) n(S) = 7
[S= { (Sun,Mon) (Mon,Tue) (Tue,Wed) (Wed,Thu) (Thu,Fri) (Fri,Sat) (Sat,Sun) }
Therefore P= n(E)/n(S) = 2/7..
- 37
Rohan Mishra answered this
2/7 is the only answer
- -3
Sameeh answered this
A leap year has 366 days.
when 366 is divided by 7,you get 52 as quotient and 2 as remainder.
Those 2 days can be MT,TW,WTh,ThF,FS,SSu,orSuM
No of favourable outcomes=2
So,P(E)=2/7
when 366 is divided by 7,you get 52 as quotient and 2 as remainder.
Those 2 days can be MT,TW,WTh,ThF,FS,SSu,orSuM
No of favourable outcomes=2
So,P(E)=2/7
- 19
Karshana B G answered this
A non - leap year contains 365 days 52 weeks and 1 day more.
i) We get 53 Sundays when the remaining day is Sunday.
Number of days in week = 7
∴ n(S) = 7
Number of ways getting 53 Sundays.
n(E) = 1
n E 1
n S 7
=
∴ Probability of getting 53 Sundays =1/7
i) We get 53 Sundays when the remaining day is Sunday.
Number of days in week = 7
∴ n(S) = 7
Number of ways getting 53 Sundays.
n(E) = 1
n E 1
n S 7
=
∴ Probability of getting 53 Sundays =1/7
- 5
Sampada answered this
366 days ➗ 7days = 52 weeks and 2 days :
These two days can be
Sunday monday
Monday tuesday
Tuesday wednesday
Wednesday Thursday
Thursday Friday
Friday Saturday
Saturday Sunday
And therefore probability is 2/7
- 0
Neha answered this
In a leap year ,total number of days =366
In 366 days there are 52 weeks and 2 days
Now two days may be
Sun and Mon
Mon andTue
Tue and Wed
Wed andThur
Thur and Fri
Fri and Sat
Sat and Sun
Now, in total 7 probabilities ,
Sun and Mon come together in one time
So,
and=1/7
- -2
Neha answered this
Hope you understand it,
- 7
Satyajeet Shivaji Bagal answered this
2/7
- 0
Sakshi answered this
2/ 7
- 0
Sai Kumar answered this
A leap year has 366 days
So no: of weeks = 52
These 52 weeks surely have 52 sundays and 52 mondays
No: of remaining days = 2
These two days could be :
{(Sun,Mon), (Mon,Tue), (Tue, Wed), (Wed,Thur), (Thur,Fri), (Fri,Sat), (Sat,Sun)}
No: of favourable outcomes (i.e., the remaining 2 days are Sunday and Monday to make it 53 sundays and 53 mondays) = 1
Total possible ways = 7
Therefore, P(E) = 1/7
So no: of weeks = 52
These 52 weeks surely have 52 sundays and 52 mondays
No: of remaining days = 2
These two days could be :
{(Sun,Mon), (Mon,Tue), (Tue, Wed), (Wed,Thur), (Thur,Fri), (Fri,Sat), (Sat,Sun)}
No: of favourable outcomes (i.e., the remaining 2 days are Sunday and Monday to make it 53 sundays and 53 mondays) = 1
Total possible ways = 7
Therefore, P(E) = 1/7
- -1
Prince Goyal answered this
1/7
1/7
1/7
- 1
Zaid answered this
ONLY AND ONLY THE THE CORRECT ANSWER IS
2/7
- 0
Sulaiman Saifuddin answered this
Please see answer below
- 0
Harr answered this
2/7 probablity
- 0
Sneha answered this
Probability of 53 Sundays are 2/7 and 53 Mondays are 2/7
- 0
Midhun M answered this
Probability is 2/7
- 0
💔😔 Devil Yash 💔🙂 answered this
Thank you for sending friend request
- 0
Madhu answered this
In a leap year the no of days is 366, right. And we also know that in a year(365) there are 52weeks.
But there is one day extra in a leap year.
So that day can be any day of the week( sunday, monday, tuesday, wednesday, thursday, friday or saturday)
In a normal year we have 52mondays right.
The probability of having 53mondays in a leap year is 1/7
Because that one extra day may be any day of the week
But there is one day extra in a leap year.
So that day can be any day of the week( sunday, monday, tuesday, wednesday, thursday, friday or saturday)
In a normal year we have 52mondays right.
The probability of having 53mondays in a leap year is 1/7
Because that one extra day may be any day of the week
- 0
Dharmendra Kumar answered this
Please find this answer
- 0
𝐀 𝐬 𝐡 𝐮 answered this
A leap year has 366 days, in which 2 days may be any one of the following pairs.
(Sunday, Monday), (Monday, Tuesday), (Tuesday, Wednesday), (Wednesday, Thursday), (Thursday, Friday), (Friday, Saturday), (Saturday, Sunday).
???Required probability?
(Sunday, Monday), (Monday, Tuesday), (Tuesday, Wednesday), (Wednesday, Thursday), (Thursday, Friday), (Friday, Saturday), (Saturday, Sunday).
???Required probability?
- 0
𝐀 𝐬 𝐡 𝐮 answered this
Dear student
Lencho went out to have the pleasure of feeling the rain on his body. He?eagerly waited for the rainfall in order to get good harvest and he became happy when it came. He compared the raindrops to new coins because the crop needed the rain badly and it was the sign of good harvest in future.
Lencho was satisfied because he thought that the rain would ensure him a good harvest and a good yield.
Draped?is the word in the extract means same as 'covered'.
He regarded?the field of ripe corn with its flowers? means that the field is occupied with ripen corn having flowers on it. And relate this field of ripe corn as?covered in a curtain of rain.
Hope it helps!!!
Regards to
Lencho went out to have the pleasure of feeling the rain on his body. He?eagerly waited for the rainfall in order to get good harvest and he became happy when it came. He compared the raindrops to new coins because the crop needed the rain badly and it was the sign of good harvest in future.
Lencho was satisfied because he thought that the rain would ensure him a good harvest and a good yield.
Draped?is the word in the extract means same as 'covered'.
He regarded?the field of ripe corn with its flowers? means that the field is occupied with ripen corn having flowers on it. And relate this field of ripe corn as?covered in a curtain of rain.
Hope it helps!!!
Regards to
- 0