# What is the answer of question 3

$Rateofpercolation=\frac{Amountofwater\left(mL\right)}{Percolationtime\left(min\right)}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}Given,Amountofwater=200mL\phantom{\rule{0ex}{0ex}}Percolationtime=50sec=\frac{50}{60}min=\frac{5}{6}min\phantom{\rule{0ex}{0ex}}\Rightarrow Rateofpercolation=\frac{200}{{\displaystyle \raisebox{1ex}{$5$}\!\left/ \!\raisebox{-1ex}{$6$}\right.}}=\frac{200*6}{5}=240\raisebox{1ex}{$mL$}\!\left/ \!\raisebox{-1ex}{$min$}\right.\phantom{\rule{0ex}{0ex}}$

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