# what is dimensional formula of young modulus

dimensional formula of Young's modulus=[M^2L^-1T^-2]
hope this helps u out....
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M1LT-1
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CORRECT RIGHT

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Dimensional​ forumla for acceleration
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Young's Modulus = Dimensions Of Pressure= M1L-1T-2
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ML-1T-2 are the dimensions .
I hope this helpd you thanks
Thumbs up plz
GDS
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What is the dimensional formula of temperature gradient??
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6c^3/ab^2
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any1 pls deduce this formula
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ML-¹T-²
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[ML-1T-2] - Young's Modulus
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ML^-1T^-2
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This is the dimensional formula for Young's modulas

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ML-1T-2
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[M].[L]^-1.[T]^-2
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ML^-1T^-1 Hope this helps! !
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ML^-1T^-2 Hope this helps ☺
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dimension of pressure is similar to that of young modulas.
so,dimension of young modulas is ML^-1T^-2
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ML^-1T^-2....this is the formula buddy
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Hope this helps....

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M1 L-1 T-2
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Young s modulus=Pressure=Bulk modulus=Modulus of rigidity=Stress.(ML-1T-2)
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ML-1T-2
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Young's modulus is same as moduluus of elasticity. Dimensions are (ML^-1T^-2)
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M1L0T-2
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Dimentional formulq for young's modulous.

Stress?strain

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ATp by utilizing proton motif force means
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ML^-1T^-2
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Dimensional formula of young's modulus is M^1L^-1T^-2. Young's modulus isn't dimensionless quantity. But it says strain is dimensionless quantity (which is true). As we know that, Young's modulus (Y) = Stress/Strain = Pressure. Young's modulus has the same dimensions as that of pressure,i.e., M^1L^-1T^-2 and its unit is also Pascal. Hope it is helpful...
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Dimensional formula for accelaration is M^0L^1T^-2
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The unit is Pascal, and can be written as N/m^2
to find N, F=ma=kgm/s^2(unit of Force is N)
DIMENSIONS OF F= MLT^-2

Now, in N/m^2,
MLT^-2 divided by L^2 (N/m^2)
=MLT^-2/L^2= ML^-1T^-2....

​​​​​​​Hope this helps....
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|Mt^-1
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M?L-?T-? is the dimensional formula for Young's Modulus of Elasticity
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M?L-?T-? is the dimensional formula for YOUNG'S MODULUS
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Young modulus = stress / strain
= F/A /?l/L
= FL/A?l
= M^1L^2T^-2/L^3
= M^1L^-1T^-2
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Young's modulus is the ratio of stress, which has units of pressure, to strain, which is dimensionless; therefore, Young's modulus has units of pressure. From my reasoning if something is dimensionless, it should be a unitless ratio.
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lol..
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Dimensional formula of Young's modulus is same as pressure
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It's dimensional formula is M^1L^-1T^-2
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FA inverse D to the power 0
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Young's modulus = Stress/Strain?
? ? ? ? ? ? ? ? ? ? ? ? ? ? = F/A x e/l
? ? ? ? ? ? ? ? ? ? ? ? ? ? = ma/A x e/l
Where,
F = force
A = area of cross section
e = elongation
l = actual length
a = acceleration?
m = mass ? ? ? ? ? ? ? ? ? ? ? ? ?
?By their units,
? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? Y = [(kg x m/s?) / (m?)] x m/m
? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? Y = (Kg x m) / (m?s?)
? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? Y = Kg/ms?

In dimension formula ? ?Y = [?M L?? S??]

Hope it helps you!!!
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This formula u can use for all the modulus till u r in +1 and plz don't forget to upvote me if u got ur ans

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Wrong question
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Ml^-1T^-2
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Young's Modulus, Y= Stress/Strain
So, [Y]= [ML^-1T^-2]
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Dimensional formula of Young's Modulus of Elastisity = Stress/strain
=[M^1 L^-1 T^-2]/[M^0 L^0 T^0]
=[M^1 L^-1 T^-2]
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Dimensions of Young's modules

= Force/Area = ML^1T^2
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This is the correct one..sorry for previous one ...camera default..

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/AB/
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Young Modulus= stress/strain
And we know that,
Stress= Force/Area
# Force=Mass ? acceleration
=M ? Velocity/time
= M ? distance/time^2
= MLT^-2
And,
strain is has a formula
Length/Length, so it's dimensionless quantity
So, stress has a dimension =
MLT^-2/L^2 which is equals to
ML^-1T^-2
Then,
Young modulus has a dimension equals to ML^-1T^-2.
??????
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ML-1T-2
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[M^1 L^-1 T^-2]
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First you have to know about stress and strain
Stress=force/area
=ML-1T-2
And strain is dimensionless
Young modulus =stress/strain
So the dimension of young modulusis same as that of stress i.e.ML-1T-2
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M^1L^-1T^-2
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ML-1T-2
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heres d ans

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what is the Chandrasekhar number
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[ML^-1T^-2]
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online classes
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ML-1T-2
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Dimensional formula of young modulus ML^-1T^-2
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MLsquar Tto the power _2
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10 th ki markshit 2010
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Aman Kumar

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It is pressure and it's formula is force\area
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Y=F/A
[Y]=[MLT^-2]/[L^2]
[Y]=[ML^-1T^2]
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M1L-1T-2
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It is unit less
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ML-t
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Y=F/A??L/L
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The?dimensional formula of Young's modulus?is [ML-1T-2].

SI unit:?Pa

Imperial unit:?psi

Dimension:?ML-1T-2
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Young's Modulus = Stress/Strain
As stress has the dimension ML^-1T^-2 and strain being dimensionless.
The dimensional formula is ML^-1T^-2.
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ML^-1T^-2
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M^1L^-1T^-2
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Ml-1T-1
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Measurement can be define as the process of comparing and non physical quantity with the help of a physical quantity.
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M^1L^-1T^-2
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[M?L-?T-?]
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ML??T??
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ML-1T-2 are the dimensions .
I hope this helpd you thanks
Thumbs up plz
GDS
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