What happens when(give balanced chemical equations and explain) -
1. Lead Nitrate Crystals are heated in a test tube
2. An iron nail is added to copper sulphate solution
3. Barium Hydroxide solution reacts with air.
4. Silver Bromide is exposed to sunlight.
Please Answer quickly. URGENT. Thanks
(1) When lead nitrate crystals are heated in a test tube, it decomposes into lead oxide, nitric oxide and oxygen. Thus, it is a decomposition reaction:
2 Pb(NO3)2 (s) → 2 PbO(s) + 4 NO2 (g) + O2 (g)
(2) When iron nail is dipped in CuSO4 solution, then red deposits of Cu on iron nail is observed alongwith fading of blue colour of CuSO4 solution. It is a type of displacement reaction:
Fe(s) + CuSO4 (l) → FeSO4 (l) + Cu(s)
(3) Barium hydroxide when reacts with Carbon-di-oxide it forms Barium Carbonate. It is a combination reaction :
Ba(OH)2 (s)+ CO2 (g) → BaCO3 (s) + H2O.(l)
If you want reaction of barium hydroxide with a specific gas present in air, then do let us know. We will be glad to help you.
(4) When silver bromide is exposed to sunlight, it undergoes decomposition to form silver and bromine. Thus, it is a decomposition reaction.
2 AgBr (s) → 2 Ag(s) + Br2 (g)