we multiply the consecutive even positive integers until the product 2*4*6*8 *n, where n is the first - Maths - Rational Numbers

Question

we multiply the consecutive even positive integers until the
product 2*4*6*8 *n, where n is the first number, for which the
product is divisible by 2015 Find the value of n

Amit Kumar · Accepted Answer

we multiply the consecutive even positive integers until the product 2*4*6*8....*n, where n is the first number, for which the product is divisible by 2015. Find the value of n

we multiply the consecutive even positive integers until the product 2468....n, where n is the first number, for which the product is divisible by 2015. Find the value of n