. Share with your friends Share 0 Atul Shaw answered this Solution:p→=2i^-4j^+7k^;q→=3i^-2j^+2k^p→×q→=i^j^k^2-473-22=i^(-8-(-14))-j^(4-21)+k^(-4-(-12))=6i^+17j^+8k^p→×q→=6i^+17j^+8k^=62+172+82=389=19.72 0 View Full Answer