# Using properties of sets prove the statements given:-(i) For all sets A and B, AU(B-A) = AUB(ii) For all sets A and B, A-(A-B) = AintersectionB(iii) For all sets A and B, (AUB)-B = A-B

1)
To show that A u (B - A) = A U B we need to show two things:
1) A U (B - A) $\subseteq$ A U B.
2) A U B $\subseteq$ A U (B - A)

First, let x $\in$A U (B - A).

In the similar way should try for the other two for your own practice.

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