Using properties of determinants prove |b+c a a | | b c+a b |=4abc | c c a+b | Share with your friends Share 11 Manbar Singh answered this Dear student Let ∆ = b+caabc+abcca+bApplying R1 = R1 + R2 + R3, we get∆ = 2b+c2c+a2a+bbc+abcca+b⇒∆ = 2b+cc+aa+bbc+abcca+bApplying R2 = R2 - R1 and R3 = R3 - R1, we get∆ = 2b+cc+aa+b-c0-a-b-a0Apply R1 = R1 + R2 + R3, we get∆ = 20cb-c0-a-b-a0=2-c0-ab + bac-0=2abc+abc=22abc=4abc Regards 43 View Full Answer
