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"Two years later a father will be 8 years more than three times the age of the son "Taking the present age of father and son as x and y respectively. Write a linear equation for teh above.Find the age of the father when son is 10 years old

Hi!
Here is the answer to your question.
 
Suppose, present age of father = x years and present age of son = y years
Two years later,
Age of father = (x + 2) years
Age of son = (y + 2) years
 
Two years later, age of father = 3 × Age of son + 8 years  [Given]
When age of son, y = 10 years, age of father, x = 3 × 10 + 12 = 30 + 12 = 42 years
 
Cheers!

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 x=3y+8

When y=10 yrs old

then y=38 yrs old

  • -20

 Suppose, present age of father = x years and present age of son = y years

Two years later,
Age of father = (x + 2) years
Age of son = (y + 2) years
 
Two years later, age of father = 3 × Age of son + 8 years  [Given]
When age of son, y = 10 years, age of father, x = 3 × 10 + 12 = 30 + 12 = 42 years
 
  • 7
Two years later,
Age of father = (x + 2) years
Age of son = (y + 2) years
 
Two years later, age of father = 3 × Age of son + 8 years  [Given]
When age of son, y = 10 years, age of father, x = 3 × 10 + 12 = 30 + 12 = 42 years
  • 7
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