two point masses of 2kg and 10kg are connected by a weight less rod of length 1.2 m. Calculate the M.I of the system about an axis passing through the centre of mass and perpendicular to the system. Share with your friends Share 5 Vara answered this Centre of mass: XCM=m1x1+m2x2m1+m2 =2×0+10×1.22+10 =1 m Determination moment of inertia: r1=XCM = 1 mr2=L-XCM = 1.2 -1 = 0.2 m I=m1r12+m2r22 =212+100.22 = 2.4 kg.m2 Answer: Moment of inertia, I=2.4 kg.m2 1 View Full Answer