Two point charges of 2c are placed at the separation of d such that electric force between them is equal to the weight of 50kg person. Find d. Share with your friends Share 0 Amit Shukla answered this Dear Student, According to the coulomb's law,the electric force between the two point charges is given by,F=Keq1q2r2where, Ke=electric constant, its value is 9×109 Nm2C-2here, q1=q2=2c and r=dand F= mg=50×9.8N=490NSo,490=9×109×2c2cd2d2=9×109×2c2490=9×108×2c249d=9×108×2c249d=3×104×2c7d=6c×1047m Regards. 1 View Full Answer
