Two particles A and B are in motion. If the momentum of A is half of that of B and if the wavelength of A is 4.5 x 102 nm, what is the wavelength of B? Share with your friends Share 2 Geetha answered this According to de-Broglie λ = hpWhere λ - wavelengthp -momentumh-planck's constantλA = hpA and λB = hpB4.5 × 10-2 = hpB2 and λB = hpBDivide the above two equation4.5 × 10-2λB = hpB2hpB4.5 × 10-2λB = 2λB =4.5 × 10-22 = 2.25 × 10-2 nm 1 View Full Answer