Two horses are considered for a race. The probability of selection of the first horse is 1/4 and that of the second is 1/3. What is the probability that :(a) both of them will be selected. (b) only one of them will be selected. (c) none of them will be selected. Share with your friends Share 11 Varun.Rawat answered this Let A be the event that the first horse is selected.Now, PA = 14 ⇒ Pfirst horse is not selected =PA = 1 - PA = 1 - 14 = 34Let B be the event that second horse is selected.Now, PB = 13 ⇒Psecond horse is not selected = PB = 1 - PB = 1 - 13 = 231.Pboth selected =PA∩B = PA . PB = 14 × 13 = 1122.Pexactly one is selected = PAB + PA¯B = PA . PB + PA . PB = 14×23+34×13 = 5123Pnone of them is selected =PAB = PA . PB = 34×23 = 12 20 View Full Answer