Two fixed frictionless inclined plane make an angle of 30degreeand 60degreewiththevertical. Two block A and Bare placed on the two planes. What is the relative vertical acceleration ofA wit respect to B.

The acceleration of block B inclined at 30° with the vertical=g cos30°=3g2and the acceleration of block A inclined at 60° with the vertical=g cos60°=g2THE RELATIVE VERTICAL ACCELERATION OF THE TWO BLOCKS=3g2 cos30°-g2 cos60°=3g2×32-g2×g2Therefore relative vertical accelerationof the two blocks=3g4-g4=g2=9.82=4.9m/s2

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