two filing pipes p and q are fitted to a tank .p is first opened for half the time taken by Q alone to fill the tank and then closed . Q is then open for half the time taken by P alone to fill the tank. If the tank is full after a total of 6 hours after p was opened, for how long was Q opened?

Dear Student,


let time taken by P to fill tank =x hourstime taken by Q to fill the tank=y hourslet total work =LCMX,Y=xywork done in 1 hour by P=xyx=ywork done by Q in 1 hour=xnow P worked first for half the time taken by q i.e. y2hence work completed by P in y2 hours=y×y2=y22work done by Q in half time taken by P=x×x2now it is given that work was done after 6 hours when P was openedhence y2+x2=6x+y=12Also since the work is completed the work done by P and Q should be equal to total work i.ey22+x22=xyx2+y2=2xyx2+y2-2xy=0x-y2=0x=yhence x=6 and y=6hence both the pipes P and Q worked equally for 62= 3 hoursHence answer is 3 hours.
Regards,

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