Two electrons are moving towards each other,each with a velocity of 106m/s What will be losest distance of approach between - Physics - Electrostatic Potential And Capacitance

Question

Two electrons are moving towards each other,each with a velocity
of 106m/s What will be losest distance of approach
between them?

Rajnish Singh · Accepted Answer

the closest distance of approach is when its total kinectic energy
is concerted into potential energy
K E = P
E2×12mv2 = k×e×er       here m = mass of electron , k = 9×109N-m2/C2 = r =k×e2mv2= 9×109×(1
6×10-19)29
1×10-31×(106)2                           = 9×2
56×109×10-389 1×10-31×1012 =2
53×10-2910-19                            =2
53×10-29+19                              =2
53×10-10 meter

Two electrons are moving towards each other,each with a velocity of 106m/s.What will be losest distance of approach between them?

Two electrons are moving towards each other,each with a velocity of 10⁶m/s.What will be losest distance of approach between them?