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try these class 8 page 175

1.   24cm2
2.  21cm2
 
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refer the solutions
 
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What's the third answer for TRY THESE Page 175?
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i.)  Area of quadrilateral ABCD = Area of Triangle ABC + Area of Triangle ACD
​Area of Triangle ABD =1/2bh = 1/2 x 6 x 3 = 9 sq.cm.
Area of Triangle ACD =1/2bh = 1/2 x 6 x 5 =15 sq.cm.

Area of Quadrilateral = (9+15) sq.cm. = 24 sq.cm. 
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ii.) Area of Rhombus = 1/2d1d2 =1/2 x 7 x 6 = 21 sq.cm.
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Area of Quadrilateral = Area of the two triangles = 2 (1/2bh) = 2(1/2 x 8 x 2) = 16 sq.cm.
 
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Please find this answer

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Hai,here your answer

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I do'n't no
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Answer of iii page no 175 try these
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Answer these quadrilateral

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Solution 1

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Please tell me this answers method

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Answer full

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Try these in page 175 those three sums

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Class 8 page 175 1st quadrilateral first we will find the area of quadrilateral area of quadrilateral is half(h1+h2)d so we will put he values in this formula and we will get the answer and rest are also same we have to apply the formaula and put the values and solve thankyou hope you understand
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Plz tell me this answer very urgent

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Try These 1st.

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Please tell answer of this question 1

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1.   24cm2
2.  21cm2
 
 
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Question no.4

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Solve question no 8 and 12

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for try these ques. 1 & 2 pg no. 173 fig 11.8 ii)

let the trapezium be abcd
then we can take the 6cm ending point as e
then we can take the another 6 cm ending point as f
area of triangle abe 15/2 cm sq
area of triangle dfc 15/2 cm sq
finally area of the rectangle ae*ef 30cm sq
then 15/2cm sq + 15/2cm sq + 30cm sq
totaly 45cm sq

 
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Page number 170 Try these solutions
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Chapter 14 try these

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Fig 11.14

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try these
solution of  (a) formula of area= 1/2d(h1+h2)
ans: 1/2^6(3+5)
ans: 1/2^6^8
ans: 1/2^48
ans 24
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ok
 
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what perimeter or area
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This is only 1 and 2 . Last one is quiet typical

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This is only 1 And 2 one. Last one is very confusing.😅

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Please find this answer

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