Three coins are tossed together find the probability of getting one head and two tail

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Please find below the solution to the asked query:

We show sample space when three coins are tossed :



We know , Probability P ( E )  = $\frac{\mathrm{Total} \mathrm{number} \mathrm{of} \mathrm{desired} \mathrm{events} \mathrm{n} ( \mathrm{E} )}{\mathrm{Total} \mathrm{number} \mathrm{of} \mathrm{events} \mathrm{n} ( \mathrm{S} )}$

So,

n ( S ) =  8

Events where we get one head and two tail = { H,T,T} , {T,H,T} and {T,T,H} , So

Number of events where we get one head and two tail = 3 , So

n ( E ) = 3

Then,

Probability of getting 1 head and 2 tail  = $\frac{\mathbf{3}}{\mathbf{8}}$                                           ( Ans )

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