Three circuits of same type wire and bulb are given 1)compare their intensity of light with reason
Dear Student,
In first two circuits, the amount of current passing through the filament wire determine the intensity of bulb as the wire is of same type therefore, their resistivities will equal or same. So, the more is the current, the more brighter is the light.
Further, in the third circuit with iron core, when the iron core is inserted inside the choke coil, the inductance (L) of coil increases. Thus, the inductive reactance (wL) of the coil increases and so, the impedance of circuit increases and current I = V/Z decreases. Consequently, the bulb becomes dim. i.e. the brightness of bulb will decrease.
Hope this information will clear your doubts about the topic.
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In first two circuits, the amount of current passing through the filament wire determine the intensity of bulb as the wire is of same type therefore, their resistivities will equal or same. So, the more is the current, the more brighter is the light.
Further, in the third circuit with iron core, when the iron core is inserted inside the choke coil, the inductance (L) of coil increases. Thus, the inductive reactance (wL) of the coil increases and so, the impedance of circuit increases and current I = V/Z decreases. Consequently, the bulb becomes dim. i.e. the brightness of bulb will decrease.
Hope this information will clear your doubts about the topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards