there are three liquids A , B , C. the mass , heat capacity and temp. of A is ( Ma, Ca , Ta) for liquid b is (Mb, Cb,Tb) and for liquid c is(Mc,Cc,Tc) respectively. if all the three liquids are mixed then final temperature will be

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As nothing is mentioned about the relation between Ta , Tb and Tc. soAssuming Tc is greater than Ta and Tb.Heat lost by A and B is equal to the heat gained by CMaCa(T-Ta)+MbCb(T-Tb)=McCc(Tc-T)MaCa(T-Ta)+MbCb(T-Tb)=McCc(Tc-T)MaCaT-MaCaTa+MbCbT-MbCbTb=McCcTc-McCcTT=(MaCaTa+MbCbTb+McCcTc)(McCc+MbCb+MaCa)Regards

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