The work done in an open vessel at 300 K, when 112 g iron reacts with dil HCl to give FeCl2 is?
Ans 1.2 kcal
The reaction involved is:
Fe +2HCl ---------->FeCl2 +H2
Work done = P(V2-V1)
Since mole of Fe used =112/56 =2
The moles of H2 formed =2
P*(VH2-Vi) = P*VH2
As Vi =0
For H2 P* VH2 = nRT
VH2 = nRT/P
W =P*nRT/P = nRT = 2*2*300=1200 cal or 1.2 kcal