# The vector component of vector A=3i+4j+5k along vector B=I+j+k is

Dear Student,

$A=3\stackrel{^}{i}+4\stackrel{^}{j}+5\stackrel{^}{k}\phantom{\rule{0ex}{0ex}}\left|A\right|=\sqrt{{3}^{2}+{4}^{2}+{5}^{2}}=\sqrt{9+16+25}=\sqrt{50}=5\sqrt{2}\phantom{\rule{0ex}{0ex}}B=\stackrel{^}{i}+\stackrel{^}{j}+\stackrel{^}{k}\phantom{\rule{0ex}{0ex}}\left|B\right|=\sqrt{{1}^{2}+{1}^{2}+{1}^{2}}=\sqrt{1+1+1}=\sqrt{3}$
The vector component of A along B is given as $\frac{5\sqrt{2}}{\sqrt{3}}\left(\stackrel{^}{i}+\stackrel{^}{j}+\stackrel{^}{k}\right)$.
Regards,

• -25
What are you looking for?