the values of observed and calculated molecular weights of silver nitrate are 90 and 170 respectively. the degree of dissociation of silver nitrate is​

Dear Student,

The computation are expressed below,

for silver nitrate the vant hoff factor is,i =Normal molar massObserved molar mass=1+α17090=1+αα=17090-1=1.889-1=0.889 α=88.9 %

Regards.

  • 11
Van't Hoff factor (i) = calculated Mol. mass / Observed Mol. mass

i = 170 / 90
i = 1.88


degree of dissociation
α = (i - 1) / (n - 1)                                     ( n = no. of ions formed after dissociation )
α = (1.88 - 1)​ / (2 - 1)                       ( The dissolution of silver nitrate from ions of silver and nitrate)
α = 0.88

 
  • 4
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