the units digit of a two digit number is 3 and seven times the sum of the digits is the number itself. find the number.
Given that –
Unit digit of the number = 3
Let tens digit of the number = x
then, the number will be = 10 × x + 3
= 10 × x + 3 ... (1)
According to Question –
10x + 3 = 7 (3 + x)
⇒ 10x + 3 = 21 + 7x
⇒ 3x = 18
⇒ x = 6
Hence, the number is 10 × 6 + 3 = 63