the two consecutive class marks of a distribution are 52 and 57. find the class limits of two intervals
class marks are 52 , 57
Therefore class size = 57-52=5
Now we know lower and upper class limits for 52 are
lower limit=52 - 5/2=49.5
upper limit=52+5/2= 54.5
Now for 57
lower limit= 57-5/2= 54.5
upper limit = 57+5/2= 59.5
Therefore we obtain