the sum of the two numbers is 25 and the reciprocals is 3/10. find the numbers

Let's assume 1st no be x

the 2nd no. is 25-x

Sum of their reciprocals = 1/x + 1/25-x = 3/10

On simplification

(25-x) + (x) = 3

25x - x2 10

= 250 = 75x - 3x2

= on solving

x = _______ or ___________

negletting negative value

ans is _________

therefore numers are ___ , 25 - ___

ans = __ , __

  • -22

Let's assume 1st no be x

the 2nd no. is 25-x

Sum of their reciprocals = 1/x + 1/25-x = 3/10

On simplification

(25-x) + (x) = 3

25x - x2 10

= 250 = 75x - 3x2

= on solving

x = _______ or ___________

negletting negative value

ans is _________

therefore numers are ___ , 25 - ___

ans = __ , __

  • -13
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