The square root of 11+root112 is?

Dear student,

Answer:

The answer is √7 + 2

Step-by-step explanation:

Here, the given expression is,

11 + \sqrt{112},

= 11 + \sqrt{4\times 28}

= 11 + \sqrt{4} \times \sqrt{28}

= 11 + 2 \times \sqrt{28}

= 11 + 2 \times \sqrt{7} \times \sqrt{4}

= 7 + 4 + 2 \times \sqrt{7} \times \sqrt{4}

= (\sqrt{7})^2 + (\sqrt{4})^2 + 2\times \sqrt{7}\times \sqrt{4}

= (\sqrt{7} + \sqrt{4})^2           [identity used: (a+b)2 = a2 +b2 + 2ab]

Thus, 11 + √112 = (√7 + √4)²

Hence,

\sqrt{11+\sqrt{112}}=\sqrt{(\sqrt{7}+\sqrt{4})^2}=\sqrt{7}+\sqrt{4}=\sqrt{7}+2


Regards

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