The solubility product constant of Ag2CrO4 and AgBr are 1 1 × 10 12 and 5 0 × 10 13 - Chemistry - Equilibrium

Question

The solubility product constant of Ag2CrO4
and AgBr are 1 1 × 10–12 and 5 0 ×
10–13 respectively Calculate the ratio of the
molarities of their saturated solutions

Prerna Bansal · Accepted Answer

Let s be the solubility of Ag2CrO4

Let s´ be the solubility of AgBr

Therefore, the ratio of the molarities of their saturated solution is

The solubility product constant of Ag2CrO4 and AgBr are 1.1 × 10–12 and 5.0 × 10–13 respectively. Calculate the ratio of the molarities of their saturated solutions.

The solubility product constant of Ag₂CrO₄ and AgBr are 1.1 × 10^–12 and 5.0 × 10^–13 respectively. Calculate the ratio of the molarities of their saturated solutions.